SDUT 2613 This is an A+B Problem

 

This is an A+B Problem

Time Limit: 1000 ms Memory Limit: 65536 KiB

Problem Description

As usual, there will be an A+B problem in warming up, this problem is:
Given two integers A and B, your job is to calculate the sum of A + B.

Input

 There are several test cases, For each test case:
There are two integers A, B for each case (0 ≤ A , B < 10¹⁰⁰⁰).

Output

 For each test case, output one line containing the result of A+B. 

Sample Input

1 2
11111111111 11111111111

Sample Output

3
22222222222

提示：这个题看似非常简单，其实他说是A+B Problem，但是其实看样例就满满的恶意，10的1000次方，用long long也过不了，
     所以这不是一个简单的A+B Problem，所以这道题要用到大数模拟，即用字符串数组模拟来完成两数相加的操作。

代码实现如下(g++):

#include <bits/stdc++.h>

using namespace std;

char s1[1010];
char s2[1010];
int ab[1010];//因为是1000次方，所以只需开1010的数组即可

int main()
{
    int i,j;
    int len1,len2,a,b;
    memset(s1,'',sizeof(s1));
    memset(s2,'',sizeof(s2));
    memset(ab,0,sizeof(ab));//重置数组
    while(~scanf("%s %s",s1,s2))
    {
        len1=strlen(s1);
        len2=strlen(s2);
        if(len1==1&&s1[0]=='0'&&len2==1&&s2[0]=='0')//当出现0+0=0时
        {
            printf("0
");
            continue;
        }                                        
        int y=0;
        for(i=len1-1,j=len2-1; i>=0||j>=0; i--,j--)
        {
            if(i>=0)
            {
                a=s1[i]-'0';
            }
            else
            {
                a=0;
            }
            if(j>=0)
            {
                b=s2[j]-'0';
            }
            else
            {
                b=0;
            }
            ab[y++]=a+b;
        }
        for(i=0; i<y; i++)
        {
            ab[i+1]+=(ab[i]/10);
            ab[i]%=10;//数组储存每一位
        }
        i=y;
        while(ab[i]==0)
        {
            i--;
        }
        for(; i>=0; i--)
        {
            printf("%d",ab[i]);
        }
        printf("
");
        memset(s1,'',sizeof(s1));
        memset(s2,'',sizeof(s2));
        memset(ab,0,sizeof(ab));//必须重置数组
    }
    return 0;
}


/***************************************************
Result: Accepted
Take time: 0ms
Take Memory: 156KB
****************************************************/