Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
Input: [1,2,3] Output: 3 Explanation: Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
public class Solution { public int minMoves(int[] nums) { // 其实就是数学问题, 全部n-1个值加1就是一个值减1 公式 sum(array)- n * min(array) int min = Integer.MAX_VALUE; int sum = 0; for(int i = 0 ; i < nums.length ; i ++){ min = Math.min(min, nums[i]); sum += nums[i]; } return sum - nums.length * min; } }