zoukankan      html  css  js  c++  java
  • HDU 1022 Train Problem I

    Problem Description
    As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes a problem, there is only one railway where all the trains stop. So all the trains come in from one side and get out from the other side. For this problem, if train A gets into the railway first, and then train B gets into the railway before train A leaves, train A can't leave until train B leaves. The pictures below figure out the problem. Now the problem for you is, there are at most 9 trains in the station, all the trains has an ID(numbered from 1 to n), the trains get into the railway in an order O1, your task is to determine whether the trains can get out in an order O2.
     
    Input
    The input contains several test cases. Each test case consists of an integer, the number of trains, and two strings, the order of the trains come in:O1, and the order of the trains leave:O2. The input is terminated by the end of file. More details in the Sample Input.
     
    Output
    The output contains a string "No." if you can't exchange O2 to O1, or you should output a line contains "Yes.", and then output your way in exchanging the order(you should output "in" for a train getting into the railway, and "out" for a train getting out of the railway). Print a line contains "FINISH" after each test case. More details in the Sample Output.
     
    Sample Input
    3 123 321 3 123 312
     
    Sample Output
    Yes. in in in out out out FINISH No. FINISH
    Hint
    Hint
    For the first Sample Input, we let train 1 get in, then train 2 and train 3. So now train 3 is at the top of the railway, so train 3 can leave first, then train 2 and train 1. In the second Sample input, we should let train 3 leave first, so we have to let train 1 get in, then train 2 and train 3. Now we can let train 3 leave. But after that we can't let train 1 leave before train 2, because train 2 is at the top of the railway at the moment. So we output "No.".
     
    判断栈的输出顺序是否合法
     
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<sstream>
    #include<algorithm>
    #include<queue>
    #include<vector>
    #include<cmath>
    #include<map>
    #include<stack>
    #include<set>
    #include<fstream>
    #include<memory>
    #include<string>
    using namespace std;
    typedef long long LL;
    #define MAXN  10
    #define INF 1000000009
    /*
    判断出栈顺序是否合法
    */
    char a[MAXN], b[MAXN], n;
    vector<string> ans;
    int main()
    {
        while (scanf("%d%s%s", &n, a, b) != EOF)
        {
            int i = 0, j = 0;
            stack<int> s;
            ans.clear();
            for (j = 0; j < n; j++)
            {
                if (s.size() && s.top() == b[j])
                {
                    ans.push_back("out");
                    s.pop();
                    continue;
                }
                if (a[i] == b[j])
                {
                    ans.push_back("in");
                    ans.push_back("out");
                    i++;
                    continue;
                }
                while (i < n&&a[i] != b[j])
                {
                    ans.push_back("in");
                    s.push(a[i++]);
                }
                if (i == n)
                {
                    printf("No.
    ");
                    break;
                }
                else
                {
                    ans.push_back("in");
                    ans.push_back("out");
                    i++;
                }
            }
            if (j == n)
            {    
                printf("Yes.
    ");
                for (i = 0; i < ans.size(); i++)
                    cout << ans[i] << endl;
            }
            printf("FINISH
    ");
        }
    }
  • 相关阅读:
    真的简单,文本文件逐行处理–用java8 Stream流的方式
    架构师最常使用的5种架构模式及其适用场景分析
    静态集成腾讯TBS X5内核WebView,从微信提取新版30M浏览器内核打包进apk
    redis入门指南(六)—— 集群
    波士顿动力狗 SPOT 权威购买指北
    Boolean源码解剖学
    SpringBoot+Mybatis整合出现org.apache.ibatis.binding.BindingException: Invalid bound statement (not found)的解决
    linux实现shell脚本监控磁盘内存达到阈值时清理catalina.out日志
    【日志】新版日志技术
    【日志】经典日志框架
  • 原文地址:https://www.cnblogs.com/joeylee97/p/6736825.html
Copyright © 2011-2022 走看看