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  • Color the ball 线段树 区间更新但点查询

    #include<iostream>
    #include<cstdio>
    #include<cmath>
    #include<cstring>
    #include<sstream>
    #include<algorithm>
    #include<queue>
    #include<deque>
    #include<iomanip>
    #include<vector>
    #include<cmath>
    #include<map>
    #include<stack>
    #include<set>
    #include<fstream>
    #include<memory>
    #include<list>
    #include<string>
    using namespace std;
    typedef long long LL;
    typedef unsigned long long ULL;
    #define MAXN 100001
    #define L 31
    #define INF 1000000009
    #define eps 0.00000001
    struct node
    {
        LL l, r, data;
    }T[MAXN*4+10];
    LL n,a[MAXN];
    LL Query(LL p, LL k)
    {
        if (T[p].l == T[p].r)
            return T[p].data;
        LL mid = (T[p].l + T[p].r) >> 1;
        LL sum = T[p].data;
        if (k <= mid)
            sum += Query(p << 1, k);
        else
            sum += Query(p << 1 | 1, k);
        return sum;
    }
    void Build(LL p, LL l, LL r)
    {
        T[p].l = l, T[p].r = r, T[p].data = 0;
        if (l == r)
        {
            T[p].data = a[l];
            return;
        }
        LL mid = (l + r) >> 1;
        Build(p << 1, l, mid);
        Build(p <<1 | 1, mid + 1, r);
    }
    void Insert(LL p, LL l, LL r, LL num)
    {
        //cout << p << ' ' << l << ' ' << r << ' ' << num << endl;
        if (l <= T[p].l&&r >= T[p].r)
        {
            T[p].data += num;
            return;
        }
        LL mid = (T[p].l + T[p].r) / 2;
        if (r <= mid)
            Insert(p << 1, l, r, num);
        else if (l > mid)
            Insert(p << 1 | 1, l, r, num);
        else
        {
            Insert(p << 1, l, mid, num);
            Insert(p << 1 | 1, mid + 1, r, num);
        }
    }
    int main()
    {
        while (scanf("%lld", &n), n)
        {
            LL t1, t2;
            memset(a, 0, sizeof(a));
            Build(1, 1, n);
            for (LL i = 1; i <= n; i++)
            {
                scanf("%lld%lld", &t1, &t2);
                Insert(1, t1, t2, 1);
            }
            for (LL i = 1; i <= n; i++)
            {
                if (i>1) printf(" ");
                printf("%lld", Query(1, i));
            }
            printf("
    ");
        }
        return 0;
    }

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    Color the ball

    Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 19857    Accepted Submission(s): 9901


    Problem Description
    N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球a开始到气球b依次给每个气球涂一次颜色。但是N次以后lele已经忘记了第I个气球已经涂过几次颜色了,你能帮他算出每个气球被涂过几次颜色吗?
     

    Input
    每个测试实例第一行为一个整数N,(N <= 100000).接下来的N行,每行包括2个整数a b(1 <= a <= b <= N)。
    当N = 0,输入结束。
     

    Output
    每个测试实例输出一行,包括N个整数,第I个数代表第I个气球总共被涂色的次数。
     

    Sample Input
    3 1 1 2 2 3 3 3 1 1 1 2 1 3 0
     

    Sample Output
    1 1 1 3 2 1
     

    Author
    8600
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  • 原文地址:https://www.cnblogs.com/joeylee97/p/6874709.html
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