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  • 47. Permutations II

    package LeetCode_47
    
    /**
     * 47. Permutations II
     * https://leetcode.com/problems/permutations-ii/description/
     *
     * Given a collection of numbers that might contain duplicates, return all possible unique permutations.
    Example:
    Input: [1,1,2]
    Output:
    [
    [1,1,2],
    [1,2,1],
    [2,1,1]
    ]

    DFS+Backtracking *
    */ class Solution { val result = ArrayList<List<Int>>() var used: BooleanArray? = null val set = HashSet<ArrayList<Int>>() fun permuteUnique(nums: IntArray): List<List<Int>> { val cur = ArrayList<Int>() used = BooleanArray(nums.size) dfs(0, cur, nums) println(result) return result } private fun dfs(start: Int, cur: ArrayList<Int>, nums: IntArray) { if (start == nums.size) { val temp = ArrayList<Int>() temp.addAll(cur) if (!set.contains(temp)) { result.add(temp) } set.add(temp) return } for (i in 0 until nums.size) { if (used!![i]) { continue } used!![i] = true cur.add(nums[i]) dfs(start + 1, cur, nums) cur.removeAt(cur.size - 1) used!![i] = false } } }
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  • 原文地址:https://www.cnblogs.com/johnnyzhao/p/12531668.html
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