package LeetCode_316 import java.lang.StringBuilder /** * 316. Remove Duplicate Letters * https://leetcode.com/problems/remove-duplicate-letters/description/ * https://www.youtube.com/watch?v=SrlvMmfG8sA * * Given a string which contains only lowercase letters, * remove duplicate letters so that every letter appear once and only once. * You must make sure your result is the smallest in lexicographical order among all possible results. Example 1: Input: "bcabc" Output: "abc" Example 2: Input: "cbacdcbc" Output: "acdb" * */ class Solution { fun removeDuplicateLetters(s: String): String { val count = IntArray(26) val used = BooleanArray(26) val sb = StringBuilder() for (c in s) { //get every latter's appear count count[c.toInt() - 'a'.toInt()]++ } for (c in s) { count[c.toInt() - 'a'.toInt()]--//because checking if same latter will be appear later,so need reduce it if (used[c.toInt() - 'a'.toInt()]) { continue } //compared order with string had append in sb while (sb.length > 0 && //if last one in sb bigger than current c (sb.get(sb.length - 1).toInt() - 'a'.toInt() > c.toInt()-'a'.toInt()) && //still have same latter at behind (count[sb.get(sb.length - 1).toInt() - 'a'.toInt()] > 0) ) { used[sb.get(sb.length - 1).toInt() - 'a'.toInt()] = false sb.deleteCharAt(sb.length - 1) } sb.append(c) used[c.toInt() - 'a'.toInt()] = true } return sb.toString() } }