package LeetCode_763 /** * 763. Partition Labels * https://leetcode.com/problems/partition-labels/description/ * * A string S of lowercase English letters is given. * We want to partition this string into as many parts as possible so that each letter appears in at most one part, * and return a list of integers representing the size of these parts. Example 1: Input: S = "ababcbacadefegdehijhklij" Output: [9,7,8] Explanation: The partition is "ababcbaca", "defegde", "hijhklij". This is a partition so that each letter appears in at most one part. A partition like "ababcbacadefegde", "hijhklij" is incorrect, because it splits S into less parts. Note: S will have length in range [1, 500]. S will consist of lowercase English letters ('a' to 'z') only. * */ class Solution { /* * solution: brute force, Time complexity:O(n^2), Space complexity:O(1); * traverse S from left to right to find the last position of current char in String, * then compare to find partition; * */ fun partitionLabels(S: String): List<Int> { val result = ArrayList<Int>() var start = 0 var end = 0 for (i in S.indices) { end = Math.max(end, S.lastIndexOf(S[i])) if (i == end) { result.add(end - start + 1) //update the start to current end start = end + 1 } } return result } }