zoukankan      html  css  js  c++  java
  • 1202. Smallest String With Swaps

    package LeetCode_1202
    
    import java.util.*
    import kotlin.collections.HashMap
    
    /**
     * 1202. Smallest String With Swaps
     * https://leetcode.com/problems/smallest-string-with-swaps/
     * You are given a string s,
     * and an array of pairs of indices in the string pairs where pairs[i] = [a, b] indicates 2 indices(0-indexed) of the string.
    You can swap the characters at any pair of indices in the given pairs any number of times.
    Return the lexicographically smallest string that s can be changed to after using the swaps.
    
    Example 1:
    Input: s = "dcab", pairs = [[0,3],[1,2]]
    Output: "bacd"
    Explaination:
    Swap s[0] and s[3], s = "bcad"
    Swap s[1] and s[2], s = "bacd"
    
    Example 2:
    Input: s = "dcab", pairs = [[0,3],[1,2],[0,2]]
    Output: "abcd"
    Explaination:
    Swap s[0] and s[3], s = "bcad"
    Swap s[0] and s[2], s = "acbd"
    Swap s[1] and s[2], s = "abcd"
    
    Example 3:
    Input: s = "cba", pairs = [[0,1],[1,2]]
    Output: "abc"
    Explaination:
    Swap s[0] and s[1], s = "bca"
    Swap s[1] and s[2], s = "bac"
    Swap s[0] and s[1], s = "abc"
    
    Constraints:
    1. 1 <= s.length <= 10^5
    2. 0 <= pairs.length <= 10^5
    3. 0 <= pairs[i][0], pairs[i][1] < s.length
    4. s only contains lower case English letters.
     * */
    class Solution {
        /*
        * solution: UnionFind + HashMap + PriorityQueue, group by words which can connect each other,
        * Time:O(nlogn), Space:O(n)
        * */
        fun smallestStringWithSwaps(s: String, pairs: List<List<Int>>): String {
            val n = s.length
            val unionFind = UnionFind(n)
            for (item in pairs) {
                unionFind.union(item[0], item[1])
            }
            val map = HashMap<Int, PriorityQueue<Char>>()
            for (i in 0 until n) {
                //check which group contains current i
                val root = unionFind.find(i)
                map.putIfAbsent(root, PriorityQueue())
                //put in queue which in same group
                map.get(root)!!.offer(s[i])
            }
            val sb = StringBuilder()
            for (i in 0 until n) {
                val root = unionFind.find(i)
                //append current group's minimum char into result
                sb.append(map.get(root)!!.poll())
            }
            return sb.toString()
        }
    }
    
    class UnionFind constructor(n: Int) {
    
        private var parent: IntArray? = null
    
        init {
            parent = IntArray(n)
            for (i in 0 until n) {
                parent!![i] = i
            }
        }
    
        fun find(p: Int): Int {
            if (parent!![p] != p) {
                parent!![p] = find(parent!![p])
            }
            return parent!![p]
        }
    
        fun union(i: Int, j: Int) {
            val parentI = find(i)
            val parentJ = find(j)
            if (parentI != parentJ) {
                parent!![parentJ] = parentI
            }
        }
    }
  • 相关阅读:
    ubuntu 14.04搭建PHP项目基本流程
    linux下 lvm 磁盘扩容
    LVM基本介绍与常用命令
    Linux LVM逻辑卷配置过程详解
    mysql 5.7中的用户权限分配相关解读!
    linux系统维护时的一些小技巧,包括系统挂载新磁盘的方法!可收藏!
    linux系统内存爆满的解决办法!~
    源、更新源时容易出现的问题解决方法
    NV显卡Ubuntu14.04更新软件导致登录死循环,不过可以进入tty模式
    一些要注意的地方
  • 原文地址:https://www.cnblogs.com/johnnyzhao/p/14266460.html
Copyright © 2011-2022 走看看