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  • c++大数模版

    http://blog.csdn.net/hackbuteer1/article/details/6595881

    #include<iostream> 
    #include<string> 
    #include<iomanip> 
    #include<algorithm> 
    using namespace std;
    
    #define MAXN 9999
    #define MAXSIZE 10
    #define DLEN 4
    
    class BigNum
    {
    private:
        int a[500];    //可以控制大数的位数 
        int len;       //大数长度
    public:
        BigNum(){ len = 1; memset(a, 0, sizeof(a)); }   //构造函数
        BigNum(const int);       //将一个int类型的变量转化为大数
        BigNum(const char*);     //将一个字符串类型的变量转化为大数
        BigNum(const BigNum &);  //拷贝构造函数
        BigNum &operator=(const BigNum &);   //重载赋值运算符,大数之间进行赋值运算
    
        friend istream& operator>>(istream&, BigNum&);   //重载输入运算符
        friend ostream& operator<<(ostream&, BigNum&);   //重载输出运算符
    
        BigNum operator+(const BigNum &) const;   //重载加法运算符,两个大数之间的相加运算 
        BigNum operator-(const BigNum &) const;   //重载减法运算符,两个大数之间的相减运算 
        BigNum operator*(const BigNum &) const;   //重载乘法运算符,两个大数之间的相乘运算 
        BigNum operator/(const int   &) const;    //重载除法运算符,大数对一个整数进行相除运算
    
        BigNum operator^(const int  &) const;    //大数的n次方运算
        int    operator%(const int  &) const;    //大数对一个int类型的变量进行取模运算    
        bool   operator>(const BigNum & T)const;   //大数和另一个大数的大小比较
        bool   operator>(const int & t)const;      //大数和一个int类型的变量的大小比较
    
        void print();       //输出大数
    };
    BigNum::BigNum(const int b)     //将一个int类型的变量转化为大数
    {
        int c, d = b;
        len = 0;
        memset(a, 0, sizeof(a));
        while (d > MAXN)
        {
            c = d - (d / (MAXN + 1)) * (MAXN + 1);
            d = d / (MAXN + 1);
            a[len++] = c;
        }
        a[len++] = d;
    }
    BigNum::BigNum(const char*s)     //将一个字符串类型的变量转化为大数
    {
        int t, k, index, l, i;
        memset(a, 0, sizeof(a));
        l = strlen(s);
        len = l / DLEN;
        if (l%DLEN)
            len++;
        index = 0;
        for (i = l - 1; i >= 0; i -= DLEN)
        {
            t = 0;
            k = i - DLEN + 1;
            if (k<0)
                k = 0;
            for (int j = k; j <= i; j++)
                t = t * 10 + s[j] - '0';
            a[index++] = t;
        }
    }
    BigNum::BigNum(const BigNum & T) : len(T.len)  //拷贝构造函数
    {
        int i;
        memset(a, 0, sizeof(a));
        for (i = 0; i < len; i++)
            a[i] = T.a[i];
    }
    BigNum & BigNum::operator=(const BigNum & n)   //重载赋值运算符,大数之间进行赋值运算
    {
        int i;
        len = n.len;
        memset(a, 0, sizeof(a));
        for (i = 0; i < len; i++)
            a[i] = n.a[i];
        return *this;
    }
    istream& operator>>(istream & in, BigNum & b)   //重载输入运算符
    {
        char ch[MAXSIZE * 4];
        int i = -1;
        in >> ch;
        int l = strlen(ch);
        int count = 0, sum = 0;
        for (i = l - 1; i >= 0;)
        {
            sum = 0;
            int t = 1;
            for (int j = 0; j<4 && i >= 0; j++, i--, t *= 10)
            {
                sum += (ch[i] - '0')*t;
            }
            b.a[count] = sum;
            count++;
        }
        b.len = count++;
        return in;
    
    }
    ostream& operator<<(ostream& out, BigNum& b)   //重载输出运算符
    {
        int i;
        cout << b.a[b.len - 1];
        for (i = b.len - 2; i >= 0; i--)
        {
            cout.width(DLEN);
            cout.fill('0');
            cout << b.a[i];
        }
        return out;
    }
    
    BigNum BigNum::operator+(const BigNum & T) const   //两个大数之间的相加运算
    {
        BigNum t(*this);
        int i, big;      //位数   
        big = T.len > len ? T.len : len;
        for (i = 0; i < big; i++)
        {
            t.a[i] += T.a[i];
            if (t.a[i] > MAXN)
            {
                t.a[i + 1]++;
                t.a[i] -= MAXN + 1;
            }
        }
        if (t.a[big] != 0)
            t.len = big + 1;
        else
            t.len = big;
        return t;
    }
    BigNum BigNum::operator-(const BigNum & T) const   //两个大数之间的相减运算 
    {
        int i, j, big;
        bool flag;
        BigNum t1, t2;
        if (*this>T)
        {
            t1 = *this;
            t2 = T;
            flag = 0;
        }
        else
        {
            t1 = T;
            t2 = *this;
            flag = 1;
        }
        big = t1.len;
        for (i = 0; i < big; i++)
        {
            if (t1.a[i] < t2.a[i])
            {
                j = i + 1;
                while (t1.a[j] == 0)
                    j++;
                t1.a[j--]--;
                while (j > i)
                    t1.a[j--] += MAXN;
                t1.a[i] += MAXN + 1 - t2.a[i];
            }
            else
                t1.a[i] -= t2.a[i];
        }
        t1.len = big;
        while (t1.a[t1.len - 1] == 0 && t1.len > 1)
        {
            t1.len--;
            big--;
        }
        if (flag)
            t1.a[big - 1] = 0 - t1.a[big - 1];
        return t1;
    }
    
    BigNum BigNum::operator*(const BigNum & T) const   //两个大数之间的相乘运算 
    {
        BigNum ret;
        int i, j, up;
        int temp, temp1;
        for (i = 0; i < len; i++)
        {
            up = 0;
            for (j = 0; j < T.len; j++)
            {
                temp = a[i] * T.a[j] + ret.a[i + j] + up;
                if (temp > MAXN)
                {
                    temp1 = temp - temp / (MAXN + 1) * (MAXN + 1);
                    up = temp / (MAXN + 1);
                    ret.a[i + j] = temp1;
                }
                else
                {
                    up = 0;
                    ret.a[i + j] = temp;
                }
            }
            if (up != 0)
                ret.a[i + j] = up;
        }
        ret.len = i + j;
        while (ret.a[ret.len - 1] == 0 && ret.len > 1)
            ret.len--;
        return ret;
    }
    BigNum BigNum::operator/(const int & b) const   //大数对一个整数进行相除运算
    {
        BigNum ret;
        int i, down = 0;
        for (i = len - 1; i >= 0; i--)
        {
            ret.a[i] = (a[i] + down * (MAXN + 1)) / b;
            down = a[i] + down * (MAXN + 1) - ret.a[i] * b;
        }
        ret.len = len;
        while (ret.a[ret.len - 1] == 0 && ret.len > 1)
            ret.len--;
        return ret;
    }
    int BigNum::operator %(const int & b) const    //大数对一个int类型的变量进行取模运算    
    {
        int i, d = 0;
        for (i = len - 1; i >= 0; i--)
        {
            d = ((d * (MAXN + 1)) % b + a[i]) % b;
        }
        return d;
    }
    BigNum BigNum::operator^(const int & n) const    //大数的n次方运算
    {
        BigNum t, ret(1);
        int i;
        if (n<0)
            exit(-1);
        if (n == 0)
            return 1;
        if (n == 1)
            return *this;
        int m = n;
        while (m>1)
        {
            t = *this;
            for (i = 1; i << 1 <= m; i <<= 1)
            {
                t = t*t;
            }
            m -= i;
            ret = ret*t;
            if (m == 1)
                ret = ret*(*this);
        }
        return ret;
    }
    bool BigNum::operator>(const BigNum & T) const   //大数和另一个大数的大小比较
    {
        int ln;
        if (len > T.len)
            return true;
        else if (len == T.len)
        {
            ln = len - 1;
            while (a[ln] == T.a[ln] && ln >= 0)
                ln--;
            if (ln >= 0 && a[ln] > T.a[ln])
                return true;
            else
                return false;
        }
        else
            return false;
    }
    bool BigNum::operator >(const int & t) const    //大数和一个int类型的变量的大小比较
    {
        BigNum b(t);
        return *this>b;
    }
    
    void BigNum::print()    //输出大数
    {
        int i;
        cout << a[len - 1];
        for (i = len - 2; i >= 0; i--)
        {
            cout.width(DLEN);
            cout.fill('0');
            cout << a[i];
        }
        cout << endl;
    }
    int main(void)
    {
        BigNum x(1234567890);
        BigNum y(x);
        cout << x + y << endl;
        cout << x - y << endl;
        cout << x * y << endl;
    
    }
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  • 原文地址:https://www.cnblogs.com/jokoz/p/4801206.html
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