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  • 排序算法

    计算时间的迭代器

    import time
    def cal_time(func):
        def wrapper(*args, **kwargs):
            t1 = time.time()
            result = func(*args, **kwargs)
            t2 = time.time()
            print("%s running time: %s secs." % (func.__name__, t2 - t1))
            return result
        return wrapper

    冒泡排序

    #coding=utf-8
    from cal_time import cal_time
    
    @cal_time
    def bubble_sort(li):
        for i in range(0,len(li)-1):
            exchange=False
            for j in range(0,len(li)-i-1):
                if li[j] > li[j+1]:
                    li[j],li[j+1]=li[j+1],li[j]
                    exchange=True
            if not exchange:
                break
    
    
    @cal_time
    def bubble_sort2(li):
        #i表示第i趟,延续区有i个数
        for i in range(len(li)-1,0,-1):
            for j in range(len(li)-1-i,0,-1):
                if li[j-1] < li[j]:
                    li[j - 1], li[j]=li[j],li[j-1]
    
    import random
    li =list(range(10000))
    random.shuffle(li)
    # bubble_sort2(li)
    bubble_sort(li)
    print(li)
    View Code

    选择排序

    from cal_time import cal_time
    
    @cal_time
    def select_sort(li):
        #第i趟,有序列li[0:i],无序列li[i,n]
        for i in range(len(li)-1):
            min_loc=i
            for j in range(i+1,len(li)):
                if li[min_loc]>li[j]:
                    min_loc=j
            li[i],li[min_loc]=li[min_loc],li[i]
    
    import random
    li=list(range(10000))
    random.shuffle(li)
    select_sort(li)
    print(li)
    View Code

    插入排序

    def insert_sort(li):
        for i in range(1,len(li)):
            #i表示趟数,也表示摸到牌的下标
            j=i-1
            tmp=li[i]
            while j>=0 and li[j]>tmp:
                li[j+1]=li[j]
                j-=1
            li[j+1]=tmp
    
    import random
    li =list(range(10000))
    random.shuffle(li)
    insert_sort(li)
    print(li)
    View Code

    快速排序

    from cal_time import cal_time
    
    def partition(li,left,right):
        i=random.randint(left,right)
        li[i],li[left]=li[left],li[i]
        tmp=li[left]
        while left<right:
            #从右边找到比tmp小的数
            while left<right and li[right]>=tmp:
                right-=1
            li[left]=li[right]
            #从左边找比temp大的数
            while left<right and li[left]<=tmp:
                left+=1
            li[right]=li[left]
        li[left]=tmp
        return left
    
    
    def _quick_sort(li,left,right):
        if left<right:
            mid=partition(li,left,right)
            _quick_sort(li,left,mid-1)
            _quick_sort(li,mid+1,right)
    
    @cal_time
    def quick_sort(li):
        return _quick_sort(li,0,len(li)-1)
    
    import random
    li=list(range(10000))
    random.shuffle(li)
    quick_sort(li)
    print(li)
    View Code

    堆排序

    from cal_time import cal_time
    
    def sift(data, low, high):
        i = low
        j = 2 * i + 1
        tmp = data[i]
        while j <= high:    #孩子在堆里
            if j + 1 <= high and data[j] < data[j+1]:   #如果有右孩子且比左孩子大
                j += 1  #j指向右孩子
            if data[j] > tmp:   #孩子比最高领导大
                data[i] = data[j]   #孩子填到父亲的空位上
                i = j               #孩子成为新父亲
                j = 2 * i +1        #新孩子
            else:
                break
        data[i] = tmp           #最高领导放到父亲位置
    
    
    @cal_time
    def heap_sort(data):
        n = len(data)
        for i in range(n // 2 - 1, -1, -1):
            sift(data, i, n - 1)
        #堆建好了
        #挨个换数
        for i in range(n-1, -1, -1):
            data[0], data[i] = data[i], data[0]
            sift(data, 0, i - 1)
    
    li=list(range(10000))
    import random
    random.shuffle(li)
    heap_sort(li)
    print(li)
    View Code

    归并排序

    def merge(li, low, mid, high):
        i = low
        j = mid + 1
        ltmp = []
        while i <= mid and j <= high:
            if li[i] <= li[j]:
                ltmp.append(li[i])
                i += 1
            else:
                ltmp.append(li[j])
                j += 1
        while i <= mid:
            ltmp.append(li[i])
            i += 1
        while j <= high:
            ltmp.append(li[j])
            j += 1
        li[low:high + 1] = ltmp
    
    
    
    def mergesort(li, low, high):
        if low < high:
            mid = (low + high) // 2
            mergesort(li, low, mid)
            mergesort(li, mid + 1, high)
            merge(li, low, mid, high)
    
    li=[2,5,7,8,9,1,3,4,6]
    mergesort(li,0,len(li)-1)
    print(li)
    View Code

    直接插入排序最好时间复杂度为O(n)

     

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  • 原文地址:https://www.cnblogs.com/jrb2018/p/10324882.html
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