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  • codeforces 1141 D 模拟

    xg

    太久没写模拟,总是写一般觉得纰漏太多

    #include <iostream>
    #include <cmath>
    #include <cstdio>
    #include <cstring>
    #include <string>
    #include <map>
    #include <iomanip>
    #include <algorithm>
    #include <queue>
    #include <stack>
    #include <set>
    #include <vector> 
    // #include <bits/stdc++.h>
    #define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    #define sp ' '
    #define endl '
    '
    #define inf  0x3f3f3f3f;
    #define FOR(i,a,b) for( int i = a;i <= b;++i)
    #define bug cout<<"--------------"<<endl
    #define P pair<int, int>
    #define fi first
    #define se second
    #define pb(x) push_back(x)
    #define ppb() pop_back()
    #define mp(a,b) make_pair(a,b)
    #define ms(v,x) memset(v,x,sizeof(v))
    #define rep(i,a,b) for(int i=a;i<=b;i++)
    #define repd(i,a,b) for(int i=a;i>=b;i--)
    #define sca3(a,b,c) scanf("%d %d %d",&(a),&(b),&(c))
    #define sca2(a,b) scanf("%d %d",&(a),&(b))
    #define sca(a) scanf("%d",&(a));
    #define sca3ll(a,b,c) scanf("%lld %lld %lld",&(a),&(b),&(c))
    #define sca2ll(a,b) scanf("%lld %lld",&(a),&(b))
    #define scall(a) scanf("%lld",&(a));
    
    
    using namespace std;
    typedef long long ll;
    ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
    ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
    ll powmod(ll a, ll b, ll mod){ll sum = 1;while (b) {if (b & 1) {sum = (sum * a) % mod;b--;}b /= 2;a = a * a % mod;}return sum;}
    
    const double Pi = acos(-1.0);
    const double epsilon = Pi/180.0;
    const int maxn = 150000+ 100; 
    vector<int>v1[30],v2[30];
    int vis1[maxn],vis2[maxn];
    char a[maxn],b[maxn];
    int main()
    {
        int n;
        cin>>n;
        queue<int>que1,que2;
        rep(i,1,n){
            char c;
            cin>>c;
            a[i] = c;
            if(c-'a' == -34) {
                que1.push(i);
                continue;
            }
            v1[c-'a'].pb(i);
        }
        rep(i,1,n){
            char c;
            cin>>c;
            b[i] = c;
            if(c-'a' == -34) {
                que2.push(i);
                continue;
            }
            v2[c-'a'].pb(i);
        }
        queue<pair<int,int> > ans;
        rep(i,0,25){
            int minn = min(v1[i].size(),v2[i].size());
            for(int j = 0; j < minn;++j){
    /*            vis1[v1[i][j]] = 1;
                vis2[v2[i][j]] = 1;*/
                ans.push(mp(v1[i][j],v2[i][j]));
            }
            if(v2[i].size() > v1[i].size()){
                while(1){
                    if(minn == v2[i].size() || que1.size() ==0){
                        break;
                    }
                    int tmp = que1.front();que1.pop();
                    ans.push(mp(tmp,v2[i][minn]));
                    minn++;
                }
            }
            else {
                 while(1){
                    if(minn == v1[i].size() || que2.size() ==0){
                        break;
                    }
                    int tmp = que2.front();que2.pop();
                    ans.push(mp(v1[i][minn],tmp));
                    minn++;
                }           
            }
        }
        while(1){
            if(que1.size() == 0 || que2.size() == 0) break;
            int x = que1.front();que1.pop();
            int y = que2.front();que2.pop();
            ans.push(mp(x,y));
        }
    
        cout<<ans.size()<<endl;
        while(ans.size()){
            int x = ans.front().fi;
            int y = ans.front().se;
            ans.pop();
            cout<<x<<sp<<y<<endl;
        }
    
    
    
    }
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  • 原文地址:https://www.cnblogs.com/jrfr/p/13329376.html
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