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  • python--二分法算法

    # 二分法查找算法,必须处理有序的算法列表
    """
    l = [2, 3, 5, 10, 15, 16, 18, 22, 26, 30, 32, 35, 41, 42, 43, 55, 56, 66, 67, 69, 72, 76, 82, 83, 88]
    def find(l,aim):
        mid_index = len(l) // 2
        if l[mid_index] < aim:
            new_l = l[mid_index + 1 :]
            find(new_l,aim)
        elif l[mid_index] > aim:
            new_l = l[:mid_index]
            find(new_l, aim)
        else:
            print("discover!!",mid_index,l[mid_index])
    find(l,66)
    """
    
    """
    l = [2, 3, 5, 10, 15, 16, 18, 22, 26, 30, 32, 35, 41, 42, 43, 55, 56, 66, 67, 69, 72, 76, 82, 83, 88]
    def find(l,aim,start = 0,end = None):
        end = len(l) if end is None else end
        mid_index = (end - start) // 2 + start
        if start <= end:
            if l[mid_index] < aim:
                return find(l,aim,start = mid_index + 1,end = end)
            elif l[mid_index] > aim:
                return find(l,aim,start=start,end=mid_index-1)
            else:
                return mid_index
        else:
            return '找不到'
    ret = find(l,66)
    print(ret)
    """
    
    # 斐波那契  # 问第n个斐波那契数是多少
    # 1, 1, 2, 3, 5, 8  # fib(6) = fib(5) + fib(4)
    """
    def fib(n,a=1,b=1):
        if n==1 : return a
        return fib(n-1,b,a+b)
    
    print(fib(5))
    """
    
    # 阶乘
    """
    def fac(n):
        if n == 1 :
            return 1
        return n * fac(n-1)
    
    print(fac(100))
    """
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  • 原文地址:https://www.cnblogs.com/jsit-dj-it/p/11443665.html
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