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  • Removing Columns 分类: 贪心 CF 2015-08-08 16:10 10人阅读 评论(0) 收藏

    Removing Columns
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    You are given an n × m rectangular table consisting of lower case English letters. In one operation you can completely remove one column from the table. The remaining parts are combined forming a new table. For example, after removing the second column from the table

    abcd
    edfg
    hijk

    we obtain the table:

    acd
    efg
    hjk

    A table is called good if its rows are ordered from top to bottom lexicographically, i.e. each row is lexicographically no larger than the following one. Determine the minimum number of operations of removing a column needed to make a given table good.
    Input

    The first line contains two integers — n and m (1 ≤ n, m ≤ 100).

    Next n lines contain m small English letters each — the characters of the table.
    Output

    Print a single number — the minimum number of columns that you need to remove in order to make the table good.
    Sample test(s)
    Input

    1 10
    codeforces

    Output

    0

    Input

    4 4
    case
    care
    test
    code

    Output

    2

    Input

    5 4
    code
    forc
    esco
    defo
    rces

    Output

    4

    Note

    In the first sample the table is already good.

    In the second sample you may remove the first and third column.

    In the third sample you have to remove all the columns (note that the table where all rows are empty is considered good by definition).

    Let strings s and t have equal length. Then, s is lexicographically larger than t if they are not equal and the character following the largest common prefix of s and t (the prefix may be empty) in s is alphabetically larger than the corresponding character of t.
    判断每一列的字符是不是符合,如果符合则判断如果上一行的字符大余这一行,则标记一下,因为后面的无论是否符合,此时的字典序已将符合.

    #include <map>
    #include <set>
    #include <list>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <string>
    #include <cstdio>
    #include <cstring>
    #include <cstdlib>
    #include <iostream>
    #include <algorithm>
    using namespace std;
    #define eps 1e-9
    #define LL long long
    #define PI acos(-1.0)
    #define INF 0x3f3f3f3f
    #define CRR fclose(stdin)
    #define CWW fclose(stdout)
    #define RR freopen("input.txt","r",stdin)
    #pragma comment(linker,"/STACK:102400000")
    #define WW freopen("output.txt","w",stdout)
    
    const int Max =  160000;
    
    char s[110][110];
    bool vis[110][110];
    int n,m;
    bool Judge(int j)
    {
        for(int i=1;i<n;i++)
        {
            if(!vis[i][i+1])
            {
                if(s[i][j]>s[i+1][j])
                {
                    return true;
                }
            }
        }
        for(int i=1;i<n;i++)
        {
            if(!vis[i][i+1])
            {
                if(s[i][j]<s[i+1][j])
                {
                    vis[i][i+1]=true;
                }
            }
        }
        return false;
    }
    int main()
    {
    
        scanf("%d %d",&n,&m);
        for(int i=1;i<=n;i++)
        {
            scanf("%s",s[i]);
        }
        int ans=0;
        memset(vis,false,sizeof(vis));
        for(int i=0;i<m;i++)
        {
            if(Judge(i))
            {
                ans++;
            }
        }
        printf("%d
    ",ans);
        return 0;
    }
    

    版权声明:本文为博主原创文章,未经博主允许不得转载。

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  • 原文地址:https://www.cnblogs.com/juechen/p/4721912.html
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