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  • BZOJ1187 [HNOI2007]神奇游乐园(插头dp)

    麻麻我会写插头dp了!

    推荐陈丹琦论文:https://wenku.baidu.com/view/3e90d32b453610661ed9f4bd.html

    破题调一年

    #include <cstdio>
    #include <cstring>
     
    const int N=1<<14;
    int n,m,tt,a1=0xcfcfcfcf,st[7],a[105][7],b[N],g[N][7],f[105][7][N];
    void up(int &x,int y) {if(x<y) x=y;}
    void dfs(int x,int s,int k) {
        if(x==m+2) {
            if(!k) {
                for(int i=0,tp=0;i<m;i++) {
                    int t=(s>>(i*2))&3;
                    if(t==2) st[++tp]=i;
                    else if(t==1) g[s][i]=st[tp],g[s][st[tp]]=i,tp--;
                }
                b[++tt]=s;
            } return;
        }
        dfs(x+1,s<<2,k),dfs(x+1,s<<2|1,k+1);
        if(k) dfs(x+1,s<<2|2,k-1);
    }
     
    int main() {
        scanf("%d%d",&n,&m);
        for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) scanf("%d",&a[i][j]);
        memset(f,0xcf,sizeof f),f[1][1][0]=0,f[1][1][(1<<(m*2))|(2*(1<<(m-1)*2))]=a[1][1],dfs(1,0,0);
        for(int i=1;i<=n;i++) {
            for(int j=1;j<m;j++) {
                for(int k=1;k<=tt;k++) if(f[i][j][b[k]]!=0xcfcfcfcf) {
                    int t1=(b[k]>>((m-j)*2))&3,t2=(b[k]>>((m-j-1)*2))&3,t3=1<<((m-j)*2),t4=1<<((m-j-1)*2);
                    int s=b[k]&((1<<((m+1)*2))-1-t3*3-t4*3),t=f[i][j][b[k]]+a[i][j+1];
                    if(!t1&&!t2) up(f[i][j+1][s],t-a[i][j+1]),up(f[i][j+1][s|t3|(t4*2)],t);
                    else if(!t1) up(f[i][j+1][s|(t3*t2)],t),up(f[i][j+1][s|(t4*t2)],t);
                    else if(!t2) up(f[i][j+1][s|(t3*t1)],t),up(f[i][j+1][s|(t4*t1)],t);
                    else if(t1==1&&t2==1) up(f[i][j+1][s-(1<<(g[b[k]][m-j-1]*2))],t);
                    else if(t1==1&&t2==2) {
                        if(b[k]==t3+t4*2&&a1<t) a1=t;
                    } else if(t1==2&&t2==1) up(f[i][j+1][s],t);
                    else up(f[i][j+1][s+(1<<(g[b[k]][m-j]*2))],t);
                }
            }
            for(int k=1;k<=tt;k++) if(f[i][m][b[k]]!=0xcfcfcfcf) {
                int t1=(b[k]>>(m*2))&3,t3=1<<(m*2),t4=1<<((m-1)*2),s=(b[k]&((1<<(m*2))-1))>>2,t=f[i][m][b[k]]+a[i+1][1];
                if(!t1) up(f[i+1][1][s],t-a[i+1][1]),up(f[i+1][1][s|t3|(t4*2)],t);
                else up(f[i+1][1][s|(t3*t1)],t),up(f[i+1][1][s|(t4*t1)],t);
            }
        }
        printf("%d",a1);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/juruolty/p/7019598.html
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