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  • 单向链表

    /*
    @@
    author:justinzhang
    email:uestczhangchao@gmail.com
    time:2012-9-1 18:51:44
    desc: all the list related operation will be place here;
          including:
          1> combine_list(list<type> *l1, list<type>* l2);
          2> list_intersect(list<type> *l1, list<type> *l2)
    @@
    */
     
    #include <iostream>
    #include <cmath>
    #include <ctime>
    using namespace std;
    template <typename type>
    class list
    {
    public:
        list<type>* create_list();
        void show_list(list<type> *lhead);
        list<type>* combine_list(list<type> *l1, list<type>* l2);
        bool list_intersect(list<type> *l1, list<type> *l2);
        type random(type begin, type end);
        type get_data()
        {
            return data;
        }
        void set_data(const type data)
        {
            this->data = data;
        }
        list<type> * get_next()
        {
            return next;
        }
        void set_next(list<type> *ne)
        {
            this->next = ne;
        }
    private:
        type data;
        list<type> *next;
    };
     
    template<typename type> type list<type>::random(type begin, type end)
    {
        return (begin + (end - begin)*rand()/(RAND_MAX+1));
    }
     
    template<typename type> void list<type>::show_list(list<type> *l)
    {
        while(l->next!=NULL)
        {
            l = l->next;
            cout << l->data << endl;
     
        }
    }
     
    /* create list with a head */
    template <typename type> list<type>* list<type> :: create_list()
    {
        type tmp_data;
        list<type> *phead = new list<type>();
        phead->next = NULL;
        list<type> *real_head = phead;
        phead->data = 11;
        
        cout << "input data, end with 111" << endl;
        while(1)
        {
            cin >> tmp_data;
            if(tmp_data == 111)
                break;
            else
            {
                list<type> *node = new list<type>();
                node->data = tmp_data;
                node->next = NULL; // do not forge this line, it's very important!
                phead->next = node;
                phead = node;
            }
     
        }
        return real_head;
    }
     
    template<typename type> list<type>* list<type>::combine_list(list<type>*l1, list<type>*l2)
    {
     
        if(l1->next==NULL)
            return l2;
        if(l2->next == NULL)
            return l1;
        list<type> * head = l1;//record the head of l1, we will link l2 after l1
        /* get last element of l1*/
        while(l1->next!=NULL)
            l1 = l1->next;
        l1->next = l2->next;
        return head;
    }
     
    template <typename type> bool list<type>::list_intersect(list<type>*l1, list<type>*l2)
    {
        while(l1->next!=NULL && l2->next!=NULL)
        {
            l1 = l1->next;
            l2 = l2->next;
            
            if(l1==l2)
                return true;
        }
        if(l1->next==NULL || l2->next==NULL)
            return false;
        else // this will not happen, but without these two lines, there will be warnings:(
            return true;
    }
     
     
    int main()
    {
        list<double> l1;
        list<double>* p1=l1.create_list();
        //l1.show_list(p1);
     
        list<double> l2;
        list<double>*p2 = l2.create_list();
        //l2.show_list(p2);
     
        /* test combine_list(p1,p2) */
        list<double>*p1_p2 = l2.combine_list(p1,p2);
        l2.show_list(p1_p2);
     
        /* test list_intersect, in oreder to make up two intersected lists,
           i will manually create them.
        */
        /*----------l3 initial-------------*/
        list<double> *l3_real = NULL;
        list<double> *l3_head = new list<double>();
        l3_head->set_data(111);
        l3_real = l3_head;
     
        list<double> *node1 = new list<double>();
        node1->set_data(1);
        l3_head->set_next(node1);
        l3_head = node1;
     
        list<double> *node2 = new list<double>();
        node2->set_data(2);
        node2->set_next(NULL);
        l3_head->set_next(node2);
        l3_head = node2;
     
        /* this is the commmon node of l3 and l4 */
        list<double> *common_node = new list<double>();
        common_node->set_data(3456);
        common_node->set_next(NULL);
        l3_head->set_next(common_node);
        l3_head = common_node;
     
        /*--------l4 initial----------*/
        list<double> *l4_real = NULL;
        list<double> *l4_head = new list<double>();
        l4_head->set_data(111);
        l4_real = l4_head;
     
        list<double> *node3 = new list<double>();
        node1->set_data(3);
        l4_head->set_next(node3);
        l4_head = node3;
     
        list<double> *node4 = new list<double>();
        node4->set_data(4);
        node4->set_next(NULL);
        l4_head->set_next(node4);
        l4_head = node4;
     
        /* l4 also points to common_node */
        l4_head->set_next(common_node);
        l4_head = common_node;
     
        if(l2.list_intersect(l3_real,l4_real))
        {
            cout << "l3 and l4 have common elements\n";
        }
        else
        {
            cout << "l3 and l4 have no common elements\n";
        }
     
        if(l2.list_intersect(p1, p2))
        {
            cout << "p1 and p2 have  common element" << endl;
        }
        else
        {
            cout << "p1 and p2 have no common element" << endl;
        }
     
     
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/justinzhang/p/2667174.html
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