【五校联考3day1】旅游

这题我们可以将询问排序，将边按照比边权从小到大排序。
在处理询问时，依次添加边，用并查集维护即可。
上标：

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
struct node{int u,v,d;}a[200010];
struct edge{int x,y;}b[500010];
int T,n,m,q,as[500010],x,y;
int siz[200010],fa[200010],ans=0,first;

inline int read()
{
	int x=0; char c=getchar();
	while (c<'0' || c>'9') c=getchar();
	while (c>='0' && c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar();
	return x;
}

int cmp(node x,node y) {return x.d<y.d;}

int cmp1(edge x,edge y) {return x.x<y.x;}

int gf(int x) {return fa[x]==x ? x:fa[x]=gf(fa[x]);}

int main()
{
//	freopen("travel.in","r",stdin);
//	freopen("travel.out","w",stdout);
	T=read();
	while (T--)
	{
		n=read(),m=read(),q=read();
		for (int i=1;i<=n;i++) siz[i]=1,fa[i]=i;
		for (int i=1;i<=m;i++)
			a[i].u=read(),a[i].v=read(),a[i].d=read();
		sort(a+1,a+m+1,cmp);
		for (int i=1;i<=q;i++) b[i].x=read(),b[i].y=i;
		sort(b+1,b+q+1,cmp1);
		first=1;ans=0;
		for (int i=1;i<=q;i++)
		{
			while (first<=m && a[first].d<=b[i].x)
			{
				x=gf(a[first].u),y=gf(a[first].v);
				if (x!=y)
				{
					ans-=siz[x]*(siz[x]-1)+siz[y]*(siz[y]-1);
					fa[x]=y,siz[y]+=siz[x];
					ans+=siz[y]*(siz[y]-1);
				}
				first++;
			}
			as[b[i].y]=ans;
		}
		for (int i=1;i<=q;i++) printf("%d
",as[i]);
	}
	return 0;
}