这一题淼,只是因为项链是一个圆,所以在头和尾的地方要注意一下!
var
a:array[1..35001] of longint;
b:array[1..35001] of char;
n,i,k,w,max:longint;
x:char;
begin
//assign(input,'necklace.in');reset(input);
//assign(output,'necklace.out');rewrite(output);
readln(n);
k:=1;
read(b[1]);
a[1]:=1;
for i:=2 to n do
begin
read(b[i]);
if (b[i]=b[i-1])or(b[i]='w')or(b[i-1]='w') then inc(a[k])
else
begin
inc(k);
w:=i-1;
a[k]:=0;
while b[w]='w' do
begin
dec(w);
inc(a[k]);
end;
end;
end;
if k=1 then
begin
writeln(a[1]);
exit;
end;
if ((b[n]=b[1])or(b[n]='w')or(b[1]='w'))and(n<>1) then
begin
a[1]:=a[1]+a[k];
a[k]:=a[1];
end;
for i:=1 to k-1 do
if a[i]+a[i+1]+1>max then max:=a[i]+a[i+1]+1;
if max>n then writeln(n)
else writeln(max);
//close(input);
//close(output);
end.