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  • 判断两条直线是否相交点

    #pragma mark ------------ 判断两条直线是否相交
     
    + (BOOL)checkLineIntersection:(CGPoint)p1 p2:(CGPoint)p2 p3:(CGPoint)p3 p4:(CGPoint)p4
    {
        CGFloat denominator = (p4.y - p3.y) * (p2.x - p1.x) - (p4.x - p3.x) * (p2.y - p1.y);
         
        if (denominator == 0.0f) {
             
            return NO;
        }
         
        CGFloat ua = ((p4.x - p3.x) * (p1.y - p3.y) - (p4.y - p3.y) * (p1.x - p3.x))/denominator;
        CGFloat ub = ((p2.x - p1.x) * (p1.y - p3.y) - (p2.y - p1.y) * (p1.x - p3.x))/denominator;
         
        if (ua >= 0.0f && ua <= 1.0f && ub >= 0.0f && ub <= 1.0f) {
             
            return YES;
        }
         
        return NO;
    }
     
    #pragma mark ------------ 两条直线要是相交 求出相交点
     
    + (CGPoint)intersectionU1:(CGPoint)u1 u2:(CGPoint)u2 v1:(CGPoint)v1 v2:(CGPoint)v2
    {
        CGPoint ret = u1;
         
        double t = ((u1.x - v1.x) * (v1.y - v2.y) - (u1.y - v1.y) * (v1.x - v2.x))/((u1.x-u2.x) * (v1.y - v2.y) - (u1.y - u2.y) * (v1.x - v2.x));
         
        ret.x += (u2.x - u1.x) * t;
        ret.y += (u2.y - u1.y) * t;
         
        return ret;
    }
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  • 原文地址:https://www.cnblogs.com/kelejiabing/p/6874982.html
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