zoukankan      html  css  js  c++  java
  • poj1573 Robot Motion

    Robot Motion
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 12507   Accepted: 6070

    Description


    A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are

    N north (up the page)
    S south (down the page)
    E east (to the right on the page)
    W west (to the left on the page)

    For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid.

    Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits.

    You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around.

    Input

    There will be one or more grids for robots to navigate. The data for each is in the following form. On the first line are three integers separated by blanks: the number of rows in the grid, the number of columns in the grid, and the number of the column in which the robot enters from the north. The possible entry columns are numbered starting with one at the left. Then come the rows of the direction instructions. Each grid will have at least one and at most 10 rows and columns of instructions. The lines of instructions contain only the characters N, S, E, or W with no blanks. The end of input is indicated by a row containing 0 0 0.

    Output

    For each grid in the input there is one line of output. Either the robot follows a certain number of instructions and exits the grid on any one the four sides or else the robot follows the instructions on a certain number of locations once, and then the instructions on some number of locations repeatedly. The sample input below corresponds to the two grids above and illustrates the two forms of output. The word "step" is always immediately followed by "(s)" whether or not the number before it is 1.

    Sample Input

    3 6 5
    NEESWE
    WWWESS
    SNWWWW
    4 5 1
    SESWE
    EESNW
    NWEEN
    EWSEN
    0 0 0

    Sample Output

    10 step(s) to exit
    3 step(s) before a loop of 8 step(s)
    

    Source

    简单的方位移动型模拟题,要用方位数组。移动模拟过程用搜索。

    15777856

      ksq2013 1573 Accepted 700K 0MS G++ 1074B 2016-07-21 22:16:18
    #include<cstdio>
    #include<cstring>
    #include<iostream>
    using namespace std;
    const int mx[]={0,+1,0,-1};
    const int my[]={+1,0,-1,0};//ESWN;
    bool vis[11][11];
    int n,m,s,mp[11][11],stp[11][11];
    void dfs(int x,int y,int cnt)
    {
        if(x<1||x>n||y<1||y>m){
            printf("%d step(s) to exit
    ",cnt);
            return;
        }
        if(vis[x][y]){
            printf("%d step(s) before a loop of %d step(s)
    ",stp[x][y],cnt-stp[x][y]);
            return;
        }
        vis[x][y]=1;
        stp[x][y]=cnt;
        int tmp=mp[x][y];
        dfs(x+mx[tmp],y+my[tmp],cnt+1);
    }
    int main()
    {
        while(scanf("%d%d%d",&n,&m,&s)&&s){
            memset(mp,0,sizeof(mp));
            memset(vis,0,sizeof(vis));
            for(int x=1;x<=n;x++){
                for(int y=1;y<=m;y++){
                    char ch;
                    cin>>ch;
                    switch(ch){
                        case 'E':mp[x][y]=0;break;
                        case 'S':mp[x][y]=1;break;
                        case 'W':mp[x][y]=2;break;
                        case 'N':mp[x][y]=3;break;
                    }
                }
            }
            dfs(1,s,0);
        }
        return 0;
    }
    


  • 相关阅读:
    Hibernate Tools-代码生成
    Java集合(二):List列表
    linux路由
    微软发布SQL Server on Linux
    微软Azure虚拟机备份服务在中国发布
    微软物联网平台再推新!
    微软宣布在Azure上支持更多的开放技术和选择
    2015年微软“十大”开源之举
    “云中论道”之——华山论剑 ,唯快不破:秘笈分享
    牛津计划折射2016年微软开源领域“大步走”
  • 原文地址:https://www.cnblogs.com/keshuqi/p/5957737.html
Copyright © 2011-2022 走看看