std::basic_string::substr
basic_string substr( size_type pos = 0, size_type count = npos );
Returns a substring [pos, pos+count). If the requested substring lasts past the end of the string, or if count == npos, the returned substring is [pos, size()).
Parameters
pos position of the first character to include
count length of the substring
Return value
String containing the substring [pos, pos+count).
Exceptions
std::out_of_range if pos > size().
Complexity
Linear in count
Example
1 #include <string> 2 #include <iostream> 3 4 int main() 5 { 6 std::string a = "0123456789abcdefghij"; 7 8 std::string sub1 = a.substr(10); 9 std::cout << sub1 << '\n'; 10 11 std::string sub2 = a.substr(5, 3); 12 std::cout << sub2 << '\n'; 13 14 std::string sub3 = a.substr(12, 100); 15 std::cout << sub3 << '\n'; 16 }
Output:
1 abcdefghij 2 567 3 cdefghij