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  • leetCode-Maximum Subarray

    Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

    For example, given the array [-2,1,-3,4,-1,2,1,-5,4], 
    the contiguous subarray [4,-1,2,1] has the largest sum = 6.

    普通版:

    class Solution {
        public int maxSubArray(int[] nums) {
            int sum = 0;
            int max = Integer.MIN_VALUE;
            int len = nums.length;
            for(int i = 0;i < len;i++){
                if(sum < 0){
                    sum = nums[i];
                }else{
                    sum += nums[i];
                }
                if(sum > max){
                    max = sum;
                }
            }
            return max;
        }
    }

    改进版(Math.max()函数的用法很巧妙):

    class Solution {
    
        public int maxSubArray(int[] nums) {
            int max = nums[0];
            int sum = nums[0];
    
            for (int i = 1; i < nums.length; i++) {
                sum = Math.max(sum + nums[i], nums[i]);
                max = Math.max(sum, max);
            }
            return max;
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/kevincong/p/7804399.html
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