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  • [HDOJ1827]Summer Holiday(强连通分量,缩点)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1827

    缩点后统计入度和当前强连通分量中最小花费,然后记录入度为0的点的个数和花费和就行了。

      1 /*
      2 ━━━━━┒ギリギリ♂ eye!
      3 ┓┏┓┏┓┃キリキリ♂ mind!
      4 ┛┗┛┗┛┃\○/
      5 ┓┏┓┏┓┃ /
      6 ┛┗┛┗┛┃ノ)
      7 ┓┏┓┏┓┃
      8 ┛┗┛┗┛┃
      9 ┓┏┓┏┓┃
     10 ┛┗┛┗┛┃
     11 ┓┏┓┏┓┃
     12 ┛┗┛┗┛┃
     13 ┓┏┓┏┓┃
     14 ┃┃┃┃┃┃
     15 ┻┻┻┻┻┻
     16 */
     17 #include <algorithm>
     18 #include <iostream>
     19 #include <iomanip>
     20 #include <cstring>
     21 #include <climits>
     22 #include <complex>
     23 #include <fstream>
     24 #include <cassert>
     25 #include <cstdio>
     26 #include <bitset>
     27 #include <vector>
     28 #include <deque>
     29 #include <queue>
     30 #include <stack>
     31 #include <ctime>
     32 #include <set>
     33 #include <map>
     34 #include <cmath>
     35 using namespace std;
     36 #define fr first
     37 #define sc second
     38 #define cl clear
     39 #define BUG puts("here!!!")
     40 #define W(a) while(a--)
     41 #define pb(a) push_back(a)
     42 #define Rint(a) scanf("%d", &a)
     43 #define Rll(a) scanf("%I64d", &a)
     44 #define Rs(a) scanf("%s", a)
     45 #define Cin(a) cin >> a
     46 #define FRead() freopen("in", "r", stdin)
     47 #define FWrite() freopen("out", "w", stdout)
     48 #define Rep(i, len) for(int i = 0; i < (len); i++)
     49 #define For(i, a, len) for(int i = (a); i < (len); i++)
     50 #define Cls(a) memset((a), 0, sizeof(a))
     51 #define Clr(a, x) memset((a), (x), sizeof(a))
     52 #define Full(a) memset((a), 0x7f7f, sizeof(a))
     53 #define pi 3.14159265359
     54 #define RT return
     55 #define lowbit(x) x & (-x)
     56 #define onenum(x) __builtin_popcount(x)
     57 typedef long long LL;
     58 typedef long double LD;
     59 typedef unsigned long long ULL;
     60 typedef pair<int, int> pii;
     61 typedef pair<string, int> psi;
     62 typedef map<string, int> msi;
     63 typedef vector<int> vi;
     64 typedef vector<LL> vl;
     65 typedef vector<vl> vvl;
     66 typedef vector<bool> vb;
     67 
     68 const int maxn = 1010;
     69 const int maxm = 2020;
     70 const int inf = 0x7f7f7f;
     71 int n, m;
     72 vector<int> G[maxn];
     73 int vis[maxn][maxn];
     74 int w[maxn];
     75 int dfn[maxn], low[maxn], idx;
     76 int st[maxn], top;
     77 int belong[maxn], bcnt;
     78 int in[maxn], out[maxn];
     79 int cost[maxn];
     80 
     81 void tarjan(int u) {
     82     int v = u;
     83     dfn[u] = low[u] = ++idx;
     84     vis[0][u] = 1; st[++top] = u;
     85     Rep(i, G[u].size()) {
     86         v = G[u][i];
     87         if(!dfn[v]) {
     88             tarjan(v);
     89             low[u] = min(low[u], low[v]);
     90         }
     91         else if(vis[0][v]) low[u] = min(low[u], dfn[v]);
     92     }
     93     if(low[u] == dfn[u]) {
     94         bcnt++;
     95         do {
     96             v = st[top--];
     97             vis[0][v] = 0;
     98             belong[v] = bcnt;
     99         } while(u != v);
    100     }
    101 }
    102 
    103 int main() {
    104     // FRead();
    105     int u, v;
    106     while(~Rint(n) && ~Rint(m)) {
    107         Cls(dfn); Cls(low); Cls(w);
    108         Cls(st); Cls(vis); top = 0;
    109         Cls(belong); bcnt = 0; idx = 0;
    110         Cls(in); Cls(out);
    111         For(i, 1, n+1) {
    112             Rint(w[i]);
    113             G[i].cl();
    114             cost[i] = inf;
    115         }
    116         Rep(i, m) {
    117             Rint(u); Rint(v);
    118             G[u].pb(v);
    119         }
    120         For(i, 1, n+1) if(!dfn[i]) tarjan(i);
    121         Cls(vis);
    122         For(u, 1, n+1) {
    123             cost[belong[u]] = min(cost[belong[u]], w[u]);
    124             Rep(i, G[u].size()) {
    125                 int v = G[u][i];
    126                 if(belong[u] == belong[v]) continue;
    127                 in[belong[v]]++;
    128                 out[belong[u]]++;
    129             }
    130         }
    131         int ret1 = 0, ret2 = 0;
    132         For(i, 1, bcnt+1) {
    133             if(in[i] == 0) {
    134                 ret1++;
    135                 ret2 += cost[i];
    136             }
    137         }
    138         printf("%d %d
    ", ret1, ret2);
    139     }
    140     RT 0;
    141 }
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  • 原文地址:https://www.cnblogs.com/kirai/p/5533761.html
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