题目链接：http://codeforces.com/contest/709/problem/C
题意：给一个字符串，选中一个连续区间修改，修改是将区间内字符顺时针转。问如何修改使得字符串字典序最小。
选中第一个非a的字符和第二个a字符之前作为区间修改即可。
1 /* 2 ━━━━━┒ギリギリ♂ eye！ 3 ┓┏┓┏┓┃キリキリ♂ mind！ 4 ┛┗┛┗┛┃＼○／ 5 ┓┏┓┏┓┃ / 6 ┛┗┛┗┛┃ノ) 7 ┓┏┓┏┓┃ 8 ┛┗┛┗┛┃ 9 ┓┏┓┏┓┃ 10 ┛┗┛┗┛┃ 11 ┓┏┓┏┓┃ 12 ┛┗┛┗┛┃ 13 ┓┏┓┏┓┃ 14 ┃┃┃┃┃┃ 15 ┻┻┻┻┻┻ 16 */ 17 #include <algorithm> 18 #include <iostream> 19 #include <iomanip> 20 #include <cstring> 21 #include <climits> 22 #include <complex> 23 #include <fstream> 24 #include <cassert> 25 #include <cstdio> 26 #include <bitset> 27 #include <vector> 28 #include <deque> 29 #include <queue> 30 #include <stack> 31 #include <ctime> 32 #include <set> 33 #include <map> 34 #include <cmath> 35 using namespace std; 36 #define fr first 37 #define sc second 38 #define cl clear 39 #define BUG puts("here!!!") 40 #define W(a) while(a--) 41 #define pb(a) push_back(a) 42 #define Rint(a) scanf("%d", &a) 43 #define Rs(a) scanf("%s", a) 44 #define Cin(a) cin >> a 45 #define FRead() freopen("in", "r", stdin) 46 #define FWrite() freopen("out", "w", stdout) 47 #define Rep(i, len) for(int i = 0; i < (len); i++) 48 #define For(i, a, len) for(int i = (a); i < (len); i++) 49 #define Cls(a) memset((a), 0, sizeof(a)) 50 #define Clr(a, x) memset((a), (x), sizeof(a)) 51 #define Full(a) memset((a), 0x7f7f7f, sizeof(a)) 52 #define lrt rt << 1 53 #define rrt rt << 1 | 1 54 #define pi 3.14159265359 55 #define RT return 56 #define lowbit(x) x & (-x) 57 #define onecnt(x) __builtin_popcount(x) 58 typedef long long LL; 59 typedef long double LD; 60 typedef unsigned long long ULL; 61 typedef pair<int, int> pii; 62 typedef pair<string, int> psi; 63 typedef pair<LL, LL> pll; 64 typedef map<string, int> msi; 65 typedef vector<int> vi; 66 typedef vector<LL> vl; 67 typedef vector<vl> vvl; 68 typedef vector<bool> vb; 69 70 const int maxn = 100100; 71 char s[maxn]; 72 int n; 73 74 void convert(int x, int y) { 75 for(int i = x; i < y; i++) { 76 if(s[i] == 'a') s[i] = 'z'; 77 else s[i]--; 78 } 79 } 80 81 int main() { 82 // FRead(); 83 while(~Rs(s)) { 84 n = strlen(s); 85 bool ok = 0; 86 int ss = 0x7f7f7f, tt = n; 87 Rep(i, n) { 88 if(s[i] != 'a') { 89 ss = i; 90 break; 91 } 92 } 93 for(int i = ss+1; i < n; i++) { 94 if(s[i] == 'a') { 95 tt = i; 96 break; 97 } 98 } 99 if(ss == 0x7f7f7f) { 100 s[n-1] = 'z'; 101 } 102 else { 103 convert(ss, tt); 104 } 105 printf("%s ", s); 106 } 107 108 RT 0; 109 }