zoukankan      html  css  js  c++  java
  • 最大子串和

    好吧,这个题目已经滥大街了,不过还是很有意思的。

    复杂的解法容易想到,O(n)的则需要一些思考。

    关键在于想明白,在遍历这个序列时,如何记录当前元素之前的最大子串和,加入当前元素后应该如何更新最大子串和。

    正好python练练手

     1 def findMaxStr(s):
     2     # start,end are array indexes(indices) of the max subsequence
     3     start = 0
     4     end = 0
     5     # cur is the maximum sum of subsequence if s[i] is included, working
     6     # accumulator
     7     cur = s[0]
     8     # maxSub is the maximum sum among all subsequences
     9     maxSub = s[0]
    10     for i in range(1, len(s)):
    11         cur += s[i]
    12         if (cur <= s[i]):
    13             cur = s[i]
    14             if(s[i] > 0):
    15                 start = i
    16             if(s[i] > maxSub):
    17                 start = i
    18                 end = i
    19         if(maxSub < cur):
    20             maxSub = cur
    21             end = i
    22     return maxSub, start, end
    23 
    24 
    25 def curRecords(seq):
    26     # make a copy of the original sequence, otherwise original values will be
    27     # changed, it is a reference.
    28     s = seq[:]
    29 
    30     for i in range(1, len(s)):
    31         # THE CRUCIAL LOGIC
    32         s[i] = max(s[i - 1] + s[i], s[i])
    33     return s
    34 
    35 
    36 def line():
    37     print("*************************************")
    38 
    39 
    40 def show(s):
    41     print (s)
    42     print (curRecords(s))
    43     print (findMaxStr(s))
    44     line()
    45 
    46 # assuming sequences contain both positive and negative values
    47 # Not assuming there are both positive and negative values, all negative sequence now return the correct result. In my opinion.
    48 s1 = [3, -4, 8, -5, 0, 2, 6, -7, 6]
    49 s2 = [-1, 3, 5, -2, 3, 0, -2, 9, -2, 3, -1]
    50 s3 = [2, -2, 3, 2, 32, -5, -2, 8, -3, 11, 0, -11, -3, 5, -1]
    51 s4 = [3, -4]
    52 s5 = [-4, 3, 56, -15, 34, 0, -14, 4]
    53 s6 = [-4, -3, -1, -5, -2]
    54 ss = [s1, s2, s3, s4, s5, s6]
    55 line()
    56 
    57 for s in ss:
    58     show(s)

    结果是这样。原序列;cur的更新过程;(最后结果,子序列起始下标,子序列结束下标)都很清楚

     1 *************************************
     2 [3, -4, 8, -5, 0, 2, 6, -7, 6]
     3 [3, -1, 8, 3, 3, 5, 11, 4, 10]
     4 (11, 2, 6)
     5 *************************************
     6 [-1, 3, 5, -2, 3, 0, -2, 9, -2, 3, -1]
     7 [-1, 3, 8, 6, 9, 9, 7, 16, 14, 17, 16]
     8 (17, 1, 9)
     9 *************************************
    10 [2, -2, 3, 2, 32, -5, -2, 8, -3, 11, 0, -11, -3, 5, -1]
    11 [2, 0, 3, 5, 37, 32, 30, 38, 35, 46, 46, 35, 32, 37, 36]
    12 (46, 2, 9)
    13 *************************************
    14 [3, -4]
    15 [3, -1]
    16 (3, 0, 0)
    17 *************************************
    18 [-4, 3, 56, -15, 34, 0, -14, 4]
    19 [-4, 3, 59, 44, 78, 78, 64, 68]
    20 (78, 1, 4)
    21 *************************************
    22 [-4, -3, -1, -5, -2]
    23 [-4, -3, -1, -5, -2]
    24 (-1, 2, 2)
    25 *************************************
  • 相关阅读:
    EasyUI datagrid动态加载json数据
    利用EasyUI combobox实现模糊搜索
    SQL动态拼接字符串生成分页存储过程
    JavaScript函数表达式
    JavaScript继承
    JavaScript创建对象的常用模式
    JavaScript引用类型
    JavaScript执行环境
    JavaScript变量及数据类型
    jackson序列化和反序列化Json
  • 原文地址:https://www.cnblogs.com/kkzxak47/p/3616919.html
Copyright © 2011-2022 走看看