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  • YY的GCD

    很抱歉,这篇文章鸽了
    回家了写(QAQ)


    (2019/9/5 UPD:)这几天有点累太久没熬夜了不太习惯只能在机房颓一颓代码,周末回去把笔记本上的推导过程丢上来吧
    先丢个代码在这里,坑待补

    // luogu-judger-enable-o2
    #include<bits/stdc++.h>
    #define int long long
    #define N (10000000 + 5)
    using namespace std;
    inline void read(int &cnt) {
    	cnt = 0; int f = 1; char c = getchar();
    	while (!isdigit(c)) {if (c == '-') f = -f; c = getchar();}
    	while (isdigit(c)) {cnt = (cnt << 3) + (cnt << 1) + (c ^ 48); c = getchar();}
    	cnt *= f;
    }
    int prime[N], T, mu[N], f[N], tot, n, m, s[N];
    int ans = 0;
    bool isprime[N];
    void init() {
    	mu[1] = 1;
    	for (register int i = 2; i <= N - 3; ++i) {
    		if (!isprime[i]) prime[++tot] = i, mu[i] = -1;
    		for (register int j = 1; j <= tot; ++j) {
    			if (prime[j] * i > N - 3) break;
    			isprime[prime[j] * i] = 1; if (i % prime[j] == 0) break;
    			mu[prime[j] * i] = -mu[i];
    		}
    	}
    	for (register int i = 1; i <= N - 3; ++i) 
    		for (register int j = 1; j <= tot; ++j)
    			if (prime[j] * i <= N - 3) f[prime[j] * i] += mu[i]; else break;
    	for (register int i = 1; i <= N - 3; ++i) s[i] = s[i - 1] + f[i]; 
    }
    signed main() {
    	read(T);
    	init();
    	while (T--) {
    		ans = 0;
    		read(n), read(m);
    		if (n > m) swap(n, m);
    		for (int l = 1, r; l <= n; l = r + 1) {
    			int x1 = n / l, x2 = m / l;
    			r = min(n / x1, m / x2);
    			ans += (s[r] - s[l - 1]) * x1 * x2;
    		} printf("%lld
    ", ans);
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/kma093/p/11461724.html
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