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  • leecode 62. 不同路径

    /*
     * 62. Unique Paths
     * 题意:求从数组[0,0]走到[m,n]的不同路径数
     * 难度:Medium
     * 分类:Array, Dynamic Programming
     * 思路:和lc63, lc64思路一样, arr存储的内容由路径数换成了和
     */
    public class lc62 {
        public static void main(String[] args) {
            System.out.println(uniquePaths(7,3));
        }
    
        public static int uniquePaths(int m, int n) {
            int[][] arr = new int[m][n];
            for (int i = 0; i < m ; i++) {
                for (int j = 0; j < n ; j++) {
                    if(i==0 && j==0)
                        arr[i][j] = 1;
                    else if(i==0)
                        arr[i][j] = arr[i][j-1];
                    else if(j==0)
                        arr[i][j] = arr[i-1][j];
                    else
                        arr[i][j] = arr[i-1][j]+arr[i][j-1];
                }
            }
            return arr[m-1][n-1];
        }
    }

    官方代码

    class Solution {
        public int uniquePaths(int m, int n) {
            int[][] f = new int[m][n];
            for (int i = 0; i < m; ++i) {
                f[i][0] = 1;
            }
            for (int j = 0; j < n; ++j) {
                f[0][j] = 1;
            }
            for (int i = 1; i < m; ++i) {
                for (int j = 1; j < n; ++j) {
                    f[i][j] = f[i - 1][j] + f[i][j - 1];
                }
            }
            return f[m - 1][n - 1];
        }
    }
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  • 原文地址:https://www.cnblogs.com/kpwong/p/14657988.html
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