解析形如(k,v)(k,v)(k,v)字符串

有时根据需要会将map数据格式化成(k,v)(k,v)(k,v)……字符串，之后需要还原，下面代码实现了还原过程

void SplitString(const string& s, vector<string>& v, const string& c)
{
    string::size_type pos1, pos2;
    pos2 = s.find(c);
    pos1 = 0;
    while(string::npos != pos2)
    {
        v.push_back(s.substr(pos1, pos2-pos1));

        pos1 = pos2 + c.size();
        pos2 = s.find(c, pos1);
    }
    if(pos1 != s.length())
        v.push_back(s.substr(pos1));
}

//格式是：(k,v)(k,v)(k,v)
void ParseAttribute(string strAttr, map<string,string>& attr)
{
    if (strAttr.empty())
    {
        return ;
    }
    vector<string> v;
    SplitString(strAttr, v, ")");
    for (int i = 0; i < v.size(); ++i)
    {
        string str = v[i];
        str.erase(str.begin(), str.begin() + str.find('(') + 1);
        vector<string> v1;
        SplitString(str, v1, ",");
        if ((v1.size() != 2) || (v1[0].empty()))
        {
            continue;
        }

        attr.insert(make_pair(v1[0], v1[1]));
    }
}