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  • ACM HDU 1164 Eddy's research I(素数分解,水题)

    Eddy's research I

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 2443    Accepted Submission(s): 1492


    Problem Description
    Eddy's interest is very extensive, recently he is interested in prime number. Eddy discover the all number owned can be divided into the multiply of prime number, but he can't write program, so Eddy has to ask intelligent you to help him, he asks you to write a program which can do the number to divided into the multiply of prime number factor .

     

    Input
    The input will contain a number 1 < x<= 65535 per line representing the number of elements of the set.
     

    Output
    You have to print a line in the output for each entry with the answer to the previous question.
     

    Sample Input
    11 9412
     

    Sample Output
    11 2*2*13*181
     

    Author
    eddy
     

    Recommend
    JGShining
     
     
    很简单,不解释了,看代码!
     
    #include<stdio.h>
    bool notprime[65536];
    void calc()
    {
    for(int i=2;i<=256;i++)
    if(notprime[i]==0)
    for(int j=i+i;j<=65535;j+=i)
    notprime[j]
    =1;
    }
    int solve(int k,int n)//得到n的>=k的素数因子
    {
    for(int i=k;i<=256;i++)
    if(notprime[i]==0)
    if(n%i==0)
    return i;
    }
    int main()
    {
    int n,i,j;
    calc();
    while(scanf("%d",&n)!=EOF)
    {
    int k=2;
    while(notprime[n])
    {
    k
    =solve(k,n);
    printf(
    "%d*",k);
    n
    /=k;
    }
    printf(
    "%d\n",n);
    }
    return 0;
    }

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  • 原文地址:https://www.cnblogs.com/kuangbin/p/2124191.html
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