zoukankan      html  css  js  c++  java
  • HDU 1036 Average is not Fast Enough!(水题)

    Average is not Fast Enough!

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 2189    Accepted Submission(s): 856


    Problem Description
    A relay is a race for two or more teams of runners. Each member of a team runs one section of the race. Your task is to help to evaluate the results of a relay race.

    You have to process several teams. For each team you are given a list with the running times for every section of the race. You are to compute the average time per kilometer over the whole distance. That's easy, isn't it?
    So if you like the fun and challenge competing at this contest, perhaps you like a relay race, too. Students from Ulm participated e.g. at the "SOLA" relay in Zurich, Switzerland. For more information visit http://www.sola.asvz.ethz.ch/ after the contest is over.
     
    Input
    The first line of the input specifies the number of sections n followed by the total distance of the relay d in kilometers. You may safely assume that 1 <= n <= 20 and 0.0 < d < 200.0. Every following line gives information about one team: the team number t (an integer, right-justified in a field of width 3) is followed by the n results for each section, separated by a single space. These running times are given in the format "h:mm:ss" with integer numbers for the hours, minutes and seconds, respectively. In the special case of a runner being disqualified, the running time will be denoted by "-:--:--". Finally, the data on every line is terminated by a newline character. Input is terminated by EOF.
     
    Output
    For each team output exactly one line giving the team's number t right aligned in a field of width 3, and the average time for this team rounded to whole seconds in the format "m:ss". If at least one of the team's runners has been disqualified, output "-" instead. Adhere to the sample output for the exact format of presentation.
     
    Sample Input
    2 12.5 5 0:23:21 0:25:01 42 0:23:32 -:--:-- 7 0:33:20 0:41:35
     
    Sample Output
    5: 3:52 min/km 42: - 7: 6:00 min/km
     
    Source
     
     
     
    很简单。。。
    就是要注意输入和输出格式。。。注意细节呢
     
     
    #include<stdio.h>
    int main()
    {
        int n;
        double d;
        int num;
        char h,m1,m2,s1,s2;
        scanf("%d",&n);
        scanf("%lf",&d);
        while(scanf("%d",&num)!=EOF)
        {
            
            printf("%3d: ",num);
            bool flag=true;
            int sumtime=0;
            for(int i=0;i<n;i++)
            {getchar();
                scanf("%c:%c%c:%c%c",&h,&m1,&m2,&s1,&s2);
                if(h=='-') flag=false;
                if(flag==false)continue;
                sumtime+=(h-'0')*3600+((m1-'0')*10+(m2-'0'))*60+(s1-'0')*10+(s2-'0');
            }    
            if(flag==false)printf("-\n");
            else
            {
                double t1=sumtime/d;
                int t2=(int)(t1+0.5);
                printf("%d:%02d min/km\n",t2/60,t2%60);
                
            }    
        }    
        return 0;
    }    
  • 相关阅读:
    【转】Android中自动连接到指定SSID的Wi-Fi
    【转】多文件目录下makefile文件递归执行编译所有c文件
    Android NDK R9d 安装
    【转】第一个MiniGUI程序:模仿QQ界面
    FFmpeg缩放swscale详解 <转>
    【转】基于Qt, TUIO和TSLIB的嵌入式Linux下的多点触摸设计
    【转】TI-Davinci开发系列之六CCS5.2调试Linux内核
    【转】ffserver用法小结
    【转】Android HAL实例解析
    【转】DM8168图像处理Link
  • 原文地址:https://www.cnblogs.com/kuangbin/p/2533315.html
Copyright © 2011-2022 走看看