BZOJ 1500: [NOI2005]维修数列 (splay tree)

1500: [NOI2005]维修数列

Time Limit: 10 Sec  Memory Limit: 64 MB
Submit: 4229  Solved: 1283
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Description

Input

输入文件的第1行包含两个数N和M，N表示初始时数列中数的个数，M表示要进行的操作数目。第2行包含N个数字，描述初始时的数列。以下M行，每行一条命令，格式参见问题描述中的表格。

Output

对于输入数据中的GET-SUM和MAX-SUM操作，向输出文件依次打印结果，每个答案（数字）占一行。

Sample Input

9 8
2 -6 3 5 1 -5 -3 6 3
GET-SUM 5 4
MAX-SUM
INSERT 8 3 -5 7 2
DELETE 12 1
MAKE-SAME 3 3 2
REVERSE 3 6
GET-SUM 5 4
MAX-SUM

Sample Output

-1
10
1
10

HINT

Source

Splay

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---

/* ***********************************************
Author        :kuangbin
Created Time  :2013/8/27 3:28:32
File Name     :F:2013ACM练习专题学习splay_tree_2维修数列.cpp
************************************************ */

#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <time.h>
using namespace std;

#define Key_value ch[ch[root][1]][0]
const int MAXN = 500010;
const int INF = 0x3f3f3f3f;
int pre[MAXN],ch[MAXN][2],key[MAXN],size[MAXN];
int root,tot1;
int sum[MAXN],rev[MAXN],same[MAXN];
int lx[MAXN],rx[MAXN],mx[MAXN];
int s[MAXN],tot2;//内存池和容量
int a[MAXN];
int n,q;

//debug部分**********************************
void Treavel(int x)
{
    if(x)
    {
        Treavel(ch[x][0]);
        printf("结点：%2d: 左儿子 %2d 右儿子 %2d 父结点 %2d size = %2d
",x,ch[x][0],ch[x][1],pre[x],size[x]);
        Treavel(ch[x][1]);
    }
}


void debug()
{
    printf("root:%d
",root);
    Treavel(root);
}
//以上是debug部分**************************************


void NewNode(int &r,int father,int k)
{
    if(tot2) r = s[tot2--];//取的时候是tot2--,存的时候就是++tot2
    else r = ++tot1;
    pre[r] = father;
    ch[r][0] = ch[r][1] = 0;
    key[r] = k;
    sum[r] = k;
    rev[r] = same[r] = 0;
    lx[r] = rx[r] = mx[r] = k;
    size[r] = 1;
}
void Update_Rev(int r)
{
    if(!r)return;
    swap(ch[r][0],ch[r][1]);
    swap(lx[r],rx[r]);
    rev[r] ^= 1;
}
void Update_Same(int r,int v)
{
    if(!r)return;
    key[r] = v;
    sum[r] = v*size[r];
    lx[r] = rx[r] = mx[r] = max(v,v*size[r]);
    same[r] = 1;
}
void push_up(int r)
{
    int lson = ch[r][0], rson = ch[r][1];
    size[r] = size[lson] + size[rson] + 1;
    sum[r] = sum[lson] + sum[rson] + key[r];
    lx[r] = max(lx[lson],sum[lson] + key[r] + max(0,lx[rson]));
    rx[r] = max(rx[rson],sum[rson] + key[r] + max(0,rx[lson]));
    mx[r] = max(0,rx[lson]) + key[r] + max(0,lx[rson]);
    mx[r] = max(mx[r],max(mx[lson],mx[rson]));
}
void push_down(int r)
{
    if(same[r])
    {
        Update_Same(ch[r][0],key[r]);
        Update_Same(ch[r][1],key[r]);
        same[r] = 0;
    }
    if(rev[r])
    {
        Update_Rev(ch[r][0]);
        Update_Rev(ch[r][1]);
        rev[r] = 0;
    }
}
void Build(int &x,int l,int r,int father)
{
    if(l > r)return;
    int mid = (l+r)/2;
    NewNode(x,father,a[mid]);
    Build(ch[x][0],l,mid-1,x);
    Build(ch[x][1],mid+1,r,x);
    push_up(x);
}
void Init()
{
    root = tot1 = tot2 = 0;
    ch[root][0] = ch[root][1] = size[root] = pre[root] = 0;
    same[root] = rev[root] = sum[root] = key[root] = 0;
    lx[root] = rx[root] = mx[root] = -INF;
    NewNode(root,0,-1);
    NewNode(ch[root][1],root,-1);
    for(int i = 0;i < n;i++)
        scanf("%d",&a[i]);
    Build(Key_value,0,n-1,ch[root][1]);
    push_up(ch[root][1]);
    push_up(root);
}
//旋转,0为左旋，1为右旋
void Rotate(int x,int kind)
{
    int y = pre[x];
    push_down(y);
    push_down(x);
    ch[y][!kind] = ch[x][kind];
    pre[ch[x][kind]] = y;
    if(pre[y])
        ch[pre[y]][ch[pre[y]][1]==y] = x;
    pre[x] = pre[y];
    ch[x][kind] = y;
    pre[y] = x;
    push_up(y);
}
//Splay调整，将r结点调整到goal下面
void Splay(int r,int goal)
{
    push_down(r);
    while(pre[r] != goal)
    {
        if(pre[pre[r]] == goal)
        {
            push_down(pre[r]);
            push_down(r);
            Rotate(r,ch[pre[r]][0] == r);
        }
        else
        {
            push_down(pre[pre[r]]);
            push_down(pre[r]);
            push_down(r);
            int y = pre[r];
            int kind = ch[pre[y]][0]==y;
            if(ch[y][kind] == r)
            {
                Rotate(r,!kind);
                Rotate(r,kind);
            }
            else
            {
                Rotate(y,kind);
                Rotate(r,kind);
            }
        }
    }
    push_up(r);
    if(goal == 0) root = r;
}
int Get_kth(int r,int k)
{
    push_down(r);
    int t = size[ch[r][0]] + 1;
    if(t == k)return r;
    if(t > k)return Get_kth(ch[r][0],k);
    else return Get_kth(ch[r][1],k-t);
}

//在第pos个数后面插入tot个数
void Insert(int pos,int tot)
{
    for(int i = 0;i < tot;i++)scanf("%d",&a[i]);
    Splay(Get_kth(root,pos+1),0);
    Splay(Get_kth(root,pos+2),root);
    Build(Key_value,0,tot-1,ch[root][1]);
    push_up(ch[root][1]);
    push_up(root);
}

//删除子树
void erase(int r)
{
    if(!r)return;
    s[++tot2] = r;
    erase(ch[r][0]);
    erase(ch[r][1]);
}
//从第pos个数开始连续删除tot个数
void Delete(int pos,int tot)
{
    Splay(Get_kth(root,pos),0);
    Splay(Get_kth(root,pos+tot+1),root);
    erase(Key_value);
    pre[Key_value] = 0;
    Key_value = 0;
    push_up(ch[root][1]);
    push_up(root);
}
//将从第pos个数开始的连续的tot个数修改为c
void Make_Same(int pos,int tot,int c)
{
    Splay(Get_kth(root,pos),0);
    Splay(Get_kth(root,pos+tot+1),root);
    Update_Same(Key_value,c);
    push_up(ch[root][1]);
    push_up(root);
}

//将第pos个数开始的连续tot个数进行反转
void Reverse(int pos,int tot)
{
    Splay(Get_kth(root,pos),0);
    Splay(Get_kth(root,pos+tot+1),root);
    Update_Rev(Key_value);
    push_up(ch[root][1]);
    push_up(root);
}
//得到第pos个数开始的tot个数的和
int Get_Sum(int pos,int tot)
{
    Splay(Get_kth(root,pos),0);
    Splay(Get_kth(root,pos+tot+1),root);
    return sum[Key_value];
}
//得到第pos个数开始的tot个数中最大的子段和
int Get_MaxSum(int pos,int tot)
{
    Splay(Get_kth(root,pos),0);
    Splay(Get_kth(root,pos+tot+1),root);
    return mx[Key_value];
}

void InOrder(int r)
{
    if(!r)return;
    push_down(r);
    InOrder(ch[r][0]);
    printf("%d ",key[r]);
    InOrder(ch[r][1]);
}



int main()
{
    //freopen("in.txt","r",stdin);
    //freopen("out.txt","w",stdout);
     while(scanf("%d%d",&n,&q) == 2)   
    {
        Init();
        char op[20];
        int x,y,z;
        while(q--)
        {
            scanf("%s",op);
            if(strcmp(op,"INSERT") == 0)
            {
                scanf("%d%d",&x,&y);
                Insert(x,y);
            }
            else if(strcmp(op,"DELETE") == 0)
            {
                scanf("%d%d",&x,&y);
                Delete(x,y);
            }
            else if(strcmp(op,"MAKE-SAME") == 0)
            {
                scanf("%d%d%d",&x,&y,&z);
                Make_Same(x,y,z);
            }
            else if(strcmp(op,"REVERSE") == 0)
            {
                scanf("%d%d",&x,&y);
                Reverse(x,y);
            }
            else if(strcmp(op,"GET-SUM") == 0)
            {
                scanf("%d%d",&x,&y);
                printf("%d
",Get_Sum(x,y));
            }
            else if(strcmp(op,"MAX-SUM") == 0)
                printf("%d
",Get_MaxSum(1,size[root]-2));
        }
    }
    return 0;
}