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  • HDUOJ

    How Many Fibs?

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 4592    Accepted Submission(s): 1803


    Problem Description
    Recall the definition of the Fibonacci numbers:
    f1 := 1
    f2 := 2
    fn := fn-1 + fn-2 (n >= 3)

    Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
     

    Input
    The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise, a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.
     

    Output
    For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b.
     

    Sample Input
    10 100 1234567890 9876543210 0 0
     

    Sample Output
    5 4
    import java.io.*;
    import java.math.*;
    import java.text.*;
    import java.util.*;
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner cin = new Scanner(System.in); 
    		BigInteger []Fib = new BigInteger[1024];
    		Fib[0] = Fib[1] = BigInteger.valueOf(1); 
    		for(int i = 2; i < 1024; i++)
    			Fib[i] = Fib[i-1].add(Fib[i-2]);
    		while(cin.hasNextBigInteger()){
    			BigInteger l = cin.nextBigInteger();
    			BigInteger r = cin.nextBigInteger();
    			int cnt = 0;
    			if(l.compareTo(BigInteger.ZERO)==0 && r.compareTo(BigInteger.ZERO)==0)
    				return ;
    			if(l.compareTo(r) > 0){
    				BigInteger t = l;
    				l = r;
    				r = t;
    			}
    			for(int i = 1; i < 1024; i++)
    				if(Fib[i].compareTo(l)>=0 && Fib[i].compareTo(r)<=0)
    					cnt++;
    			System.out.println(cnt);
    		}
    			
    	}
    
    }
    


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  • 原文地址:https://www.cnblogs.com/kunsoft/p/5312762.html
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