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  • 《DSP using MATLAB》Problem 8.11

    代码:

    %% ------------------------------------------------------------------------
    %%            Output Info about this m-file
    fprintf('
    ***********************************************************
    ');
    fprintf('        <DSP using MATLAB> Problem 8.11 
    
    ');
    banner();
    %% ------------------------------------------------------------------------
    
    %d = 0.10
    %d = 0.05
    d = 0.01
    
    a1 = (2-d)/(1+d);
    a2 = (2-d)*(1-d)/((2+d)*(1+d));
    
    % digital IIR 2nd-order allpass filter
    b = [a2  a1  1]
    a = [1  a1  a2]
    
    figure('NumberTitle', 'off', 'Name', 'Problem 8.11 Pole-Zero Plot')
    set(gcf,'Color','white'); 
    zplane(b,a); 
    title(sprintf('Pole-Zero Plot, d=%.2f',d));
    %pzplotz(b,a);
    
    [db, mag, pha, grd, w] = freqz_m(b, a);
    
    % ---------------------------------------------------------------------
    %  Choose the gain parameter of the filter, maximum gain is equal to 1 
    % ---------------------------------------------------------------------
    gain1=max(mag)                    % with poles
    K = 1
    [db, mag, pha, grd, w] = freqz_m(K*b, a);
    
    figure('NumberTitle', 'off', 'Name', 'Problem 8.11 IIR allpass filter')
    set(gcf,'Color','white'); 
    
    subplot(2,2,1); plot(w/pi, db); grid on; axis([0 2 -60 10]); 
    set(gca,'YTickMode','manual','YTick',[-60,-30,0])
    set(gca,'YTickLabelMode','manual','YTickLabel',['60';'30';' 0']);
    set(gca,'XTickMode','manual','XTick',[0,0.25,0.5,1,1.5,1.75,2]);
    xlabel('frequency in pi units'); ylabel('Decibels'); title('Magnitude Response in dB');
    
    subplot(2,2,3); plot(w/pi, mag); grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Absolute'); title('Magnitude Response in absolute');
    set(gca,'XTickMode','manual','XTick',[0,0.25,0.5,1,1.5,1.75,2]);
    set(gca,'YTickMode','manual','YTick',[0,1.0]);
    
    subplot(2,2,2); plot(w/pi, pha); grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Rad'); title('Phase Response in Radians');
    
    subplot(2,2,4); plot(w/pi, grd*pi/180);  grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Rad'); title('Group Delay');
    set(gca,'XTickMode','manual','XTick',[0,0.25,0.5,1,1.5,1.75,2]);
    %set(gca,'YTickMode','manual','YTick',[0,1.0]);
    
    
    figure('NumberTitle', 'off', 'Name', 'Problem 8.11 IIR allpass filter')
    set(gcf,'Color','white'); 
    plot(w/pi, -pha/w); grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Rad'); title('Phase Delay in samples');
    
    
    
    % Impulse Response
    fprintf('
    ----------------------------------');
    fprintf('
    Partial fraction expansion method: 
    ');
    [R, p, c] = residuez(K*b,a)
    MR = (abs(R))'              % Residue  Magnitude
    AR = (angle(R))'/pi         % Residue  angles in pi units
    Mp = (abs(p))'              % pole  Magnitude
    Ap = (angle(p))'/pi         % pole  angles in pi units
    [delta, n] = impseq(0,0,20);
    h_chk = filter(K*b,a,delta);      % check sequences
    
    
    % ------------------------------------------------------------------------------------------------
    %                                gain parameter K  
    % ------------------------------------------------------------------------------------------------
    %h =  0.2202 * ((-0.9385) .^ n) + (-0.8308) * ((-0.7887) .^ n) + 1.3509 * delta;    %d=0.1
    %h =  0.1099 * ((-0.9688) .^ n) + (-0.4112) * ((-0.8884) .^ n) + 1.1619 * delta;    %d=0.05
    h =  0.0220 * ((-0.9937) .^ n) + (-0.0820) * ((-0.9766) .^ n) + 1.0305 * delta;    %d=0.01
    % ------------------------------------------------------------------------------------------------
    
    
    figure('NumberTitle', 'off', 'Name', 'Problem 8.11 IIR allpass filter, h(n) by filter and Inv-Z ')
    set(gcf,'Color','white'); 
    
    subplot(2,1,1); stem(n, h_chk); grid on; %axis([0 2 -60 10]); 
    xlabel('n'); ylabel('h\_chk'); title('Impulse Response sequences by filter');
    
    subplot(2,1,2); stem(n, h); grid on; %axis([0 1 -100 10]); 
    xlabel('n'); ylabel('h'); title('Impulse Response sequences by Inv-Z');
    
    
    [db, mag, pha, grd, w] = freqz_m(h, [1]);
    
    
    figure('NumberTitle', 'off', 'Name', 'Problem 8.11 IIR filter, h(n) by Inv-Z ')
    set(gcf,'Color','white'); 
    
    subplot(2,2,1); plot(w/pi, db); grid on; axis([0 2 -60 10]); 
    set(gca,'YTickMode','manual','YTick',[-60,-30,0])
    set(gca,'YTickLabelMode','manual','YTickLabel',['60';'30';' 0']);
    set(gca,'XTickMode','manual','XTick',[0,0.25,1,1.75,2]);
    xlabel('frequency in pi units'); ylabel('Decibels'); title('Magnitude Response in dB');
    
    subplot(2,2,3); plot(w/pi, mag); grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Absolute'); title('Magnitude Response in absolute');
    set(gca,'XTickMode','manual','XTick',[0,0.25,1,1.75,2]);
    set(gca,'YTickMode','manual','YTick',[0,1.0]);
    
    subplot(2,2,2); plot(w/pi, pha); grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Rad'); title('Phase Response in Radians');
    
    subplot(2,2,4); plot(w/pi, grd*pi/180);  grid on; %axis([0 1 -100 10]); 
    xlabel('frequency in pi units'); ylabel('Rad'); title('Group Delay');
    set(gca,'XTickMode','manual','XTick',[0,0.25,1,1.75,2]);
    %set(gca,'YTickMode','manual','YTick',[0,1.0]);
    

      运行结果:

           这里放d=0.1的运行结果。

            二阶全通滤波器的留数、极点

            系统零极点图,可以看出,两个零点都在单位圆外,幅角为π

            方法一,利用系统函数直接形式,将脉冲序列做输入,得到脉冲响应h,得到系统幅度谱、相位谱和群延迟,如下图

            方法二,将二阶全通系统函数部分分式展开,然后查表求逆z变换,得到脉冲响应h_chk

            幅度谱、相位谱和群延迟,可以看到,ω=π时,幅度有衰减

            可见,两种方法得到的脉冲响应h有区别,我们将各自前21个元素列出来,方框处二者稍有区别。

    但,为何有区别,没搞懂,欢迎各位博友不吝赐教。

    牢记: 1、如果你决定做某事,那就动手去做;不要受任何人、任何事的干扰。2、这个世界并不完美,但依然值得我们去为之奋斗。
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  • 原文地址:https://www.cnblogs.com/ky027wh-sx/p/11005807.html
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