zoukankan      html  css  js  c++  java
  • 有向图—拓扑排序,Kosaraju算法

    有向图基本算法

    1. 对于有向图的结构,和无向图类似,甚至更简单,有疑问请留言。
      1>有向图的数据结构
    package graphTheory;
    /**
      * @author luoz 
      * @date 2016年9月19日 下午9:26:21 
    **/
    public class Digraph {
    
        private final int V;
        private int E;
        private Bag<Integer>[] adj;
    
        public Digraph(int V)
        {
            this.V = V;
            this.E = 0;
            adj = (Bag<Integer>[])new Bag[V];
            for(int i = 0;i<V;i++)
                adj[i] = new Bag<>();
        }
    
        public int V()
        {
            return V;
        }
        public int E()
        {
            return E;
        }
    
        public void addEdge(int v,int w)
        {
            adj[v].add(w);
            E++;
        }
    
        public Iterable<Integer> adj(int v)
        {
            return adj[v];
        }
    
        public Digraph reverse()
        {
            Digraph g = new Digraph(V);
            for(int j = 0; j<V;j++)
                for(int w : adj[j])
                    g.addEdge(w,j);
            return g;
        }
    }
    
    1. 基于深度优先遍历的顶点排序
      1>前序:在递归调用之前将顶点加入队列;
      2>后序:在递归调用之后将顶点加入队列;
      3>逆后序:在递归调用之后将顶点压入栈;
    package graphTheory;
    
    import java.util.*;
    import javax.management.Query;
    
    /**
      * @author luoz 
      * @date 2016年9月19日 下午10:11:48 
    **/
    public class DepthFirstOrder {
    
        private boolean[] marked;
        //pre order
        private Queue<Integer> pre;
        //postorder
        private Queue<Integer> post;
        //reverse postorder
        private Stack<Integer> repost;
    
        public DepthFirstOrder(Digraph g)
        {
            marked = new boolean[g.V()];
            pre = new LinkedList<>();
            post =  new LinkedList<>();
            repost = new Stack<>();
            for(int i = 0;i<g.V();i++)
                if(!marked[i])
                    dfs(g,i);
        }
    
        private void dfs(Digraph g,int v)
        {
            pre.add(v);
            marked[v] = true;
            for(int w : g.adj(v))
                if(!marked[w])
                    dfs(g,w);
            post.add(v);
            repost.add(v);
        }
    
        public Iterable<Integer> pre()
        {
            return pre;
        }
    
        public Iterable<Integer> post()
        {
            return post;
        }
    
        public Iterable<Integer> reversepost() {
            return repost;
        }
    }
    
    1. 检测有无环
    package graphTheory;
    
    import java.io.File;
    import java.util.Stack;
    
    /**
      * @author  luoz 
      * @date 2016年9月19日 下午9:48:41 
    **/
    public class DirectedCycle {
    
        private boolean[] marked;
        private int[] edgeTo;
    
        //All vertices of a directed loop
        private Stack<Integer> cycle;
        //resursion all vertices of the cycle 
        private boolean[] onStack;
    
        private boolean marked(int v)
        {
            return marked[v];
        }
    
        public boolean hasCycle()
        {
            return cycle != null;
        }
    
        public DirectedCycle(Digraph g)
        {
            marked = new boolean[g.V()];
            edgeTo = new int[g.V()];
            onStack = new boolean[g.V()];
            for(int i = 0;i<g.V();i++)
                if(!marked[i])
                    dfs(g,i);
        }
    
        private void dfs(Digraph g,int v)
        {
            marked[v] = true;
            onStack[v] = true;
            for(int w : g.adj(v))
            {
                if(this.hasCycle())
                    return;
                else if(!marked[w])
                {
                    edgeTo[w] = v;
                    dfs(g,w);
                }
                else if(onStack[w])
                {
                    cycle = new Stack<Integer>();
                    for(int i = v; i != w; i = edgeTo[i])
                        cycle.push(i);
                    cycle.push(w);
                    cycle.push(v);
                }
                onStack[v] = false;
            }       
        }
    
        public Iterable<Integer> cycle()
        {
            return cycle;
        }
        /*测试代码,从文件中读取的,可以自己写测试代码*/
        public static void main(String[] args) {
            FileIo fileio = new FileIo();
            String s = fileio.characterReader(new File("cycle.txt"));
            String[] st = s.split(",");
    
            Digraph g = new Digraph(13);
    
            int E = st.length;
            for(int i = 0;i<E;i++)
            {
                String[] str = st[i].split(" ");
                g.addEdge(Integer.parseInt(str[0]),Integer.parseInt(str[1]));           
            }
            DirectedCycle cc = new DirectedCycle(g);
            System.out.println(cc.hasCycle());
            System.out.println(cc.cycle);
        }
    
    }
    

    拓扑排序

    拓扑排序只针对有向无环图。
    一幅有向无环图的拓扑排序,也就是所有顶点的逆后序排列。

    package graphTheory;
    
    /**
      * @author  luoz
      * @date 2016年9月20日 上午8:30:05 
    **/
    public class Topological {
    
        private Iterable<Integer> order;
    
        public Topological(Digraph g)
        {
            DirectedCycle hascycle = new DirectedCycle(g);
            if(!hascycle.hasCycle())
            {
                DepthFirstOrder df = new DepthFirstOrder(g);
                order = df.reversepost();
            }   
        }
    
        public Iterable<Integer> order()
        {
            return order;
        }
    }

    Kosaraju算法

    计算强连通分量的算法。
    主要运用了图G的反转和顶点排序的逆后序。

    package graphTheory;
    /**
      * @author  luoz
      * @date 2016年9月20日 上午9:08:53 
    **/
    public class KosarajuSCC {
    
        private boolean[] marked;
        private int[] id;
        private int count;
    
        public KosarajuSCC(Digraph g)
        {
            marked = new boolean[g.V()];
            id = new int[g.V()];
            //
            DepthFirstOrder df = new DepthFirstOrder(g.reverse()); 
            for(int i : df.reversepost())  
                if(!marked[i])
                {
                    dfs(g,i);
                    count++;
                }
        }
        private void dfs(Digraph g,int v)
        {
            marked[v] = true;
            id[v] = count;
            for(int w :g.adj(v))
                if(!marked[w])
                    dfs(g,w);
        }
        public int count()
        {
            return count;
        }
    
        public boolean connected(int v,int w)
        {
            return id[v] == id[w];
        }
    }
    

    算法第四版

  • 相关阅读:
    CF1359D Yet Another Yet Another Task
    【数据结构】fhq_treap
    AtCoder Beginner Contest 182 题解
    UVA11992 Fast Matrix Operations
    双指针例题
    python使用国内镜像库
    APP元素定位工具之——Weditor
    安卓ADB的常见命令的使用
    函数进阶之迭代器,递归
    函数基础之对象,嵌套,名称空间和作用域
  • 原文地址:https://www.cnblogs.com/l0zh/p/13739765.html
Copyright © 2011-2022 走看看