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  • Parencodings

    http://poj.org/problem?id=1068

     1 #include<stdio.h>
     2 #include<string.h>
     3 int main()
     4 {
     5     int a[101],b[102],v[101];
     6     int t,n;
     7     scanf("%d",&t);
     8     while(t--)
     9     {
    10         scanf("%d",&n);
    11         memset(a,0,sizeof(a));
    12         for (int i = 1; i <= n; i++)
    13         {
    14             scanf("%d",&a[i]);
    15         }
    16         int o = 0;
    17         for (int i = 1; i <= n; i ++)
    18         {
    19             int k = a[i]-a[i-1];
    20             if(k > 0)
    21             {
    22                 while(k--)
    23                 {
    24                     v[o++] = 0;
    25                 }
    26                 v[o++] = 1;
    27             }
    28             else if (k==0)
    29             {
    30                 v[o++] = 1;
    31             }
    32 
    33         }
    34         int tt = 0,j,p;
    35         for (int i = 0; i < o; i ++)
    36         {
    37             int cnt = 0;
    38             if(v[i]==1)
    39             {
    40                 for (j = i-1; j >= 0; j --)
    41                 {
    42                     if (v[j]==0)
    43                     {
    44                         v[j] = -1;
    45                         break;
    46                     }
    47                 }
    48                 for (p = j; p <= i; p ++)
    49                 {
    50                     if(v[p]==1)
    51                         ++cnt;
    52                 }
    53                 b[tt++] = cnt;
    54             }
    55         }
    56         printf("%d",b[0]);
    57         for (int i = 1; i < tt; i ++)
    58             printf(" %d",b[i]);
    59         puts("");
    60     }
    61     return  0;
    62 }
    View Code
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  • 原文地址:https://www.cnblogs.com/lahblogs/p/3241795.html
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