zoukankan      html  css  js  c++  java
  • Wormholes

    http://poj.org/problem?id=3259

    spfa判断负环

     1 #include <stdio.h>
     2 #include <string.h>
     3 #include <queue>
     4 
     5 const int oo = 1<<30;
     6 const int maxn = 2011;
     7 const int maxm = maxn*maxn;
     8 struct node{
     9     int u;
    10     int v;
    11     int w;
    12     int next;
    13 }edge[maxm];
    14 int n, m, cnt;
    15 int head[maxn], dis[maxn], num[maxn];
    16 bool vis[maxn];
    17 
    18 void init(){
    19     cnt = 0;
    20     for(int i = 0; i <= n; i++){
    21         head[i] = -1;
    22         num[i] = 0;
    23         dis[i] = oo;
    24         vis[i] = false;
    25     }
    26 }
    27 
    28 void add(int u, int v, int w){
    29     edge[cnt].u = u;
    30     edge[cnt].v = v;
    31     edge[cnt].w = w;
    32     edge[cnt].next = head[u];
    33     head[u] = cnt++;
    34 }
    35 
    36 bool spfa(int s){
    37     std::queue<int>qu;
    38     qu.push(s);
    39     dis[s] = 0;
    40     num[s] = 1;
    41     vis[s] = true;
    42     while(!qu.empty()){
    43         int u = qu.front();
    44         qu.pop();
    45         vis[u] = false;
    46         for(int i = head[u]; i != -1; i = edge[i].next){
    47             int v = edge[i].v;
    48             int w = edge[i].w;
    49             if(dis[u]+w < dis[v]){
    50                 dis[v] = dis[u]+w;
    51                 if(!vis[v]){
    52                     qu.push(v);
    53                     vis[v] = true;
    54                     ++num[v];
    55                     if(num[v] > n) return false;
    56                 }
    57             }
    58         }
    59     }
    60     return true;
    61 }
    62 
    63 int main(){
    64     int t;
    65     scanf("%d", &t);
    66     while(t--){
    67         int ww;
    68         scanf("%d%d%d", &n, &m, &ww);
    69         init();
    70         for (int i = 1; i <= m; i++){
    71             int u, v, w;
    72             scanf("%d%d%d", &u, &v, &w);
    73             add(u, v, w);
    74             add(v, u, w);
    75         }
    76         for (int j = 1; j <= ww; j++){
    77             int u, v, w;
    78             scanf("%d%d%d",&u, &v, &w);
    79             add(u, v, -w);
    80         }
    81         if(!spfa(1)) printf("YES
    ");
    82         else printf("NO
    ");
    83     }
    84     return 0;
    85 }
    View Code
  • 相关阅读:
    POJ2516 构图+k次费用流
    POJ 1511 最短路径之和(spfa或dijkstra+heap)
    windows中配置mongodb
    原型设计
    Erlang的参考资源
    用Erlang实现递归查找文件
    list相关的习题
    springmvc基础知识
    汇编实验4
    实验3 转移指令跳转原理及其简单应用编程
  • 原文地址:https://www.cnblogs.com/lahblogs/p/3248413.html
Copyright © 2011-2022 走看看