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  • mysql生成日期的辅助表

    为了解决mysql按日期分组查询统计的时候,没有数据补0。可以生成连续的时间表格来辅助查询
    * 生成按天的数据

    * 每一个小时为一个分段 生成如下辅助表


    *代码如下
    CREATE TABLE num ( i INT );
    -- 创建一个表用来储存0-9的数字
    INSERT INTO num ( i )
    VALUES
        ( 0 ),
        ( 1 ),
        ( 2 ),
        ( 3 ),
        ( 4 ),
        ( 5 ),
        ( 6 ),
        ( 7 ),
        ( 8 ),
        ( 9 );
        
    -- --------------------------------------------------------------

    CREATE TABLE IF NOT EXISTS calendar ( datelist date, datehour datetime ); -- -------------------------------------------------------------- INSERT INTO calendar ( datelist ) SELECT -- 生成按天的数据 adddate( ( -- 这里的起始日期,你可以换成当前日期 DATE_FORMAT( "2018-11-10", '%Y-%m-%d' ) ), numlist.id ) AS `date` FROM ( SELECT n1.i + n10.i * 10 + n100.i * 100 + n1000.i * 1000+ n10000.i * 10000 AS id FROM num n1 CROSS JOIN num AS n10 CROSS JOIN num AS n100 CROSS JOIN num AS n1000 CROSS JOIN num AS n10000 ) AS numlist; -- -------------------------------------------------------------- INSERT INTO calendar ( datehour ) SELECT -- 生成按小时的数据 DATE_ADD( ( DATE_FORMAT( "2018-11-10", '%Y-%m-%d' ) ), INTERVAL numlist.id HOUR ) AS `date` FROM ( SELECT n1.i + n10.i * 10 + n100.i * 100 + n1000.i * 1000+ n10000.i * 10000 AS id FROM num n1 CROSS JOIN num AS n10 CROSS JOIN num AS n100 CROSS JOIN num AS n1000 CROSS JOIN num AS n10000 ) AS numlist;


     * 按天查询

    SELECT
        date( datelist ) datas,
        count( * ) - 1 AS counts 
    FROM
        (
    SELECT
        datelist 
    FROM
        calendar 
    WHERE
        ( '2018-11-17' <= date( datelist ) ) 
        AND ( date( datelist ) <= '2018-11-19' ) UNION ALL
    SELECT
        createtime 
    FROM
        snap_face
        LEFT JOIN device ON snap_face.deviceID = device.id 
    WHERE
        ( '2018-11-17' <= date( snap_face.createtime ) ) 
        AND ( date( snap_face.createtime ) <= '2018-11-19' ) 
        ) temp 
    GROUP BY
        datas 
    ORDER BY
        datas;

    * 按小时查询

    SELECT
        DATE_FORMAT(datehour,'%Y-%m-%d %H') datas,
        count( * ) - 1 AS counts 
    FROM
        (
    SELECT
    DATE_FORMAT(datehour,'%Y-%m-%d %H') datehour
    FROM
        calendar 
    WHERE
        ( '2018-11-17' <= date( datehour ) ) 
        AND ( date( datehour ) <= '2018-11-19' ) UNION ALL
    SELECT
    DATE_FORMAT(createtime,'%Y-%m-%d %H') 
    FROM
        snap_face
        LEFT JOIN device ON snap_face.deviceID = device.id 
    WHERE
        ( '2018-11-17' <= date( snap_face.createtime ) ) 
        AND ( date( snap_face.createtime ) <= '2018-11-19' ) 
        ) temp 
    GROUP BY
        datas 
    ORDER BY
        datas;
     
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  • 原文地址:https://www.cnblogs.com/lancelee98/p/10006710.html
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