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  • PLSQL 的简单命令之五

    --1.  查询和Zlotkey相同部门的员工姓名和雇用日期
    select a.last_name,a.hire_date ,b.department_name 
    from employees a,departments b
    where b.department_name in 
    (select department_name 
    from departments, employees
    where  last_name = 'Zlotkey')
    
    --2.  查询工资比公司平均工资高的员工的员工号,姓名和工资。
    select job_id,last_name,salary 
    from employees 
    where salary >  all (select avg(salary) from employees)
    
    --3.  查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资
    select a.job_id,a.last_name,a.department_id,a.salary,b.avgsalary
    from employees a,(select avg(salary) as avgsalary,department_id from employees 
    group by department_id) b
    where a.salary > b.avgsalary and a.department_id = b.department_id
    /*
    其中各部门的平均工资如下
    select avg(salary),department_id from employees 
    group by department_id
    
     别名为b的表(查询结果的表 )
    (select avg(salary) as avgsalary,department_id from employees 
    group by department_id) b
    */
    
    --4.  查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名
    select job_id,last_name,department_id
    from employees
    where department_id in (select department_id 
    from employees 
    where last_name like '%u%')
    
    --5. 查询在部门的location_id为1700的部门工作的员工的员工号
    select job_id
    from employees
    where department_id 
    in (select department_id 
    from departments 
    where location_id =1700) 
    
    --6.查询管理者是King的员工姓名和工资
    select manager_id,last_name,salary from employees
    where manager_id 
    in (select employee_id 
    from employees 
    where last_name='King'
    group by employee_id)
    
    
    --1.  运行以下脚本创建表my_employees
    create table my_employees 
                 (id number,
                  first_name varchar2(10),
                  last_name varchar2(10),
                  userid varchar2(10),
                  salary number
                  );
    --2.  显示表my_employees的结构
    select * from my_employees
    
    /*3.  向表中插入下列数据
    ID  FIRST_NAME  LAST_NAME   USERID   SALARY
    1     patel       Ralph    Rpatel   895
    2     Dancs      Betty     Bdancs    860
    3   Biri       Ben      Bbiri     1100
    4   Newman      Chad     Cnewman  750
    5  Ropeburn   Audrey    Aropebur 1550
    */  
    insert into my_employees values (1,'patel','Ralph','Rpatel',895);
    insert into my_employees values (2,'Dancs','Betty','Bdancs',860);
    insert into my_employees values (3,'Biri','Ben','Bbiri',1100);
    insert into my_employees values (4,'Newman','Chad','Cnewman',750);
    insert into my_employees values (5,'Ropeburn','Audrey','Aropebur',1550);
    
    --4.  提交
    commit
    
    --5.  将3号员工的last_name修改为“drelxer”
    update my_employees set last_name='drelxer' 
    where id = 3
    
    --6.  将所有工资少于900的员工的工资修改为1000
    update my_employees set salary=1000 where salary < 900
    
    --7.  检查所作的修正
    select * from my_employees
    
    --8.  提交
    commit
    
    --9.  删除所有数据
    delete from my_employees
    
    --10.  检查所作的修正
    select * from my_employees
    
    --11.  回滚
    rollback
    
    --12.  清空表my_employees
    truncate table my_employees
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  • 原文地址:https://www.cnblogs.com/lantu1989/p/6126557.html
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