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  • [leetcode] Word Pattern

    题目:

    Given a pattern and a string str, find if str follows the same pattern.
    
    Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.
    
    Examples:
    pattern = "abba", str = "dog cat cat dog" should return true.
    pattern = "abba", str = "dog cat cat fish" should return false.
    pattern = "aaaa", str = "dog cat cat dog" should return false.
    pattern = "abba", str = "dog dog dog dog" should return false.
    Notes:
    You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.

    分析:此题完全可以用一个map解答,注意下面代码中红色的部分。

        public boolean wordPattern(String pattern, String str) {
            char[] patArr = pattern.toCharArray();
            String[] strArr = str.split(" ");
            if (patArr.length != strArr.length) {
                return false;
            }
            HashMap<Character, String> hm = new HashMap<Character, String>();
            for (int i = 0; i < strArr.length; i++) {
                if (! hm.containsKey(patArr[i])) {
                    if (hm.containsValue(strArr[i])) {
                        return false;
                    }
                    hm.put(patArr[i], strArr[i]);
                } else {
                    if (! hm.get(patArr[i]).equals(strArr[i])) {
                        return false;
                    }
                }
            }
            return true;
        }
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  • 原文地址:https://www.cnblogs.com/lasclocker/p/4928035.html
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