题目描述
给定一个数组和滑动窗口的大小,找出所有滑动窗口里数值的最大值。例如,如果输入数组{2,3,4,2,6,2,5,1}及滑动窗口的大小3,那么一共存在6个滑动窗口,他们的最大值分别为{4,4,6,6,6,5}; 针对数组{2,3,4,2,6,2,5,1}的滑动窗口有以下6个: {[2,3,4],2,6,2,5,1}, {2,[3,4,2],6,2,5,1}, {2,3,[4,2,6],2,5,1}, {2,3,4,[2,6,2],5,1}, {2,3,4,2,[6,2,5],1}, {2,3,4,2,6,[2,5,1]}。
1 class Solution {
2 public:
3 vector<int> maxInWindows(const vector<int>& num, unsigned int size)
4 {
5 int length = num.size();
6 vector<int> res;
7 if(length < size || size == 0)
8 return res;
9 int Max = -1;
10 for(int i = 0;i <= length - size;i ++){
11 Max = num[i];
12 for(int j = i + 1;j < i + size;j ++)
13 if(Max < num[j]) Max = num[j];
14 res.push_back(Max);
15 }
16 return res;
17 }
18 };