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  • HDU 3966 Aragorn's Story(树链剖分)

    HDU Aragorn's Story

    题目链接

    树抛入门裸题,这题是区间改动单点查询,于是套树状数组就OK了

    代码:

    #include <cstdio>
    #include <cstring>
    #include <vector>
    #include <algorithm>
    using namespace std;
    
    const int N = 50005;
    
    inline int lowbit(int x) {return x&(-x);}
    
    int dep[N], fa[N], son[N], sz[N], top[N], id[N], idx;
    vector<int> g[N];
    
    int bit[N];
    
    int n, m, p, val[N];
    
    void dfs1(int u, int f, int d) {
    	dep[u] = d;
    	sz[u] = 1;
    	fa[u] = f;
    	son[u] = 0;
    	for (int i = 0; i < g[u].size(); i++) {
    		int v = g[u][i];
    		if (v == f) continue;
    		dfs1(v, u, d + 1);
    		sz[u] += sz[v];
    		if (sz[son[u]] < sz[v])
    			son[u] = v;
    	}
    }
    
    void dfs2(int u, int tp) {
    	id[u] = ++idx;
    	top[u] = tp;
    	if (son[u]) dfs2(son[u], tp);
    	for (int i = 0; i < g[u].size(); i++) {
    		int v = g[u][i];
    		if (v == fa[u] || v == son[u]) continue;
    		dfs2(v, v);
    	}
    }
    
    void add(int x, int v) {
    	while (x < N) {
    		bit[x] += v;
    		x += lowbit(x);
    	}
    }
    
    void add(int l, int r, int v) {
    	add(l, v);
    	add(r + 1, -v);
    }
    
    void gao(int u, int v, int w) {
    	int tp1 = top[u], tp2 = top[v];
    	while (tp1 != tp2) {
    		if (dep[tp1] < dep[tp2]) {
    			swap(tp1, tp2);
    			swap(u, v);
    		}
    		add(id[tp1], id[u], w);
    		u = fa[tp1];
    		tp1 = top[u];
    	}
    	if (dep[u] > dep[v]) swap(u, v);
    	add(id[u], id[v], w);
    }
    
    int query(int x) {
    	int ans = 0;
    	while (x) {
    		ans += bit[x];
    		x -= lowbit(x);
    	}
    	return ans;
    }
    
    int main() {
    	while (~scanf("%d%d%d", &n, &m, &p)) {
    		idx = 0;
    		memset(bit, 0, sizeof(bit));
    		for (int i = 1; i <= n; i++) {
    			scanf("%d", &val[i]);
    			g[i].clear();
    		}
    		int u, v;
    		while (m--) {
    			scanf("%d%d", &u, &v);
    			g[u].push_back(v);
    			g[v].push_back(u);
    		}
    		dfs1(1, -1, 1);
    		dfs2(1, 1);
    		for (int i = 1; i <= n; i++) add(id[i], id[i], val[i]);
    		char q[2];
    		int a, b, c;
    		while (p--) {
    			scanf("%s", q);
    			if (q[0] == 'I' || q[0] == 'D') {
    				scanf("%d%d%d", &a, &b, &c);
    				if (q[0] == 'D') c = -c;
    				gao(a, b, c);
    			} else {
    				scanf("%d", &a);
    				printf("%d
    ", query(id[a]));
    			}
    		}
    	}
    	return 0;
    }


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  • 原文地址:https://www.cnblogs.com/lcchuguo/p/5155582.html
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