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  • expdp导出卡住问题诊断

    本文链接:https://blog.csdn.net/guogang83/article/details/78800487
    [oracle@database ~]$nohup expdp gg/gg directory=gg_DB dumpfile=gg_20171212_%u.dmp logfile=gg_zc_20171212.log parallel=4 job_name=exp_gg_20171212 filesize=20g  cluster=no  compression=DATA_ONLY &
    ...................................................
    Estimate in progress using BLOCKS method...
    Processing object type SCHEMA_EXPORT/TABLE/TABLE_DATA
    导出一直卡在这里。

    1.刚开始以为是ESTIMATE的问题,ESTIMATE默认是BLOCKS 。
    ESTIMATE 计算作业估计值。
    有效的关键字值为: [BLOCKS] 和 STATISTICS。
    于是把调整了一下,ESTIMATE=STATISTICS,结果还是卡住。

    2.回归这个问题,那就要找到它到底在做什么,怎么看呢?
    select s.EVENT,s.MODULE,s.PROGRAM from gv$session s where s.PROGRAM like '%(DW%';(也可以查MODULE=Data Pump Worker)
    看到了有行锁enq: TX - contention,

    3.查下谁堵塞了它,kill session,可以导出了。
    SELECT bs.INST_ID,
           bs.username "Blocking User",  
           bs.username "DB User",  
           bs.SID "SID",  
           bs.serial# "Serial#",  
           bs.sql_address "address",  
           bs.sql_hash_value "Sql hash",  
           bs.program "Blocking App",     
           bs.machine "Blocking Machine",   
           bs.osuser "Blocking OS User",   
           bs.serial# "Serial#",                        
           ws.username "Waiting User",  
           ws.SID "WSID",  
           ws.program "Waiting App",  
           ws.machine "Waiting Machine",  
           ws.osuser "Waiting OS User",  
           ws.serial# "WSerial#",  
           wk.TYPE lock_type,  
           hk.lmode mode_held,  
           wk.request mode_requested,  
           TO_CHAR(hk.id1) lock_id1,  
           TO_CHAR(hk.id2) lock_id2,  
           hk.BLOCK blocking_others  
      FROM gv$lock hk, gv$session bs, gv$lock wk, gv$session ws  
     WHERE hk.BLOCK = 1  
       AND hk.lmode != 0  
       AND hk.lmode != 1  
       AND wk.request != 0  
       AND wk.TYPE(+) = hk.TYPE  
       AND wk.id1(+) = hk.id1  
       AND wk.id2(+) = hk.id2  
       AND hk.SID = bs.SID(+)  
       AND wk.SID = ws.SID(+)  
       AND (bs.username IS NOT NULL)  
       AND (bs.username <> 'SYSTEM')  
       AND (bs.username <> 'SYS')  
     ORDER BY 1; 
     
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  • 原文地址:https://www.cnblogs.com/lcword/p/11779617.html
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