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  • b站数据库课3之子查询

    #子查询
    /*
    说明:当一个查询语句中又嵌套了另一个完整的select语句,则被嵌套的select语句称为子查询或内查询
    外面的select语句称为主查询或外查询。


    分类:

    按子查询出现的位置进行分类:

    1、select后面
    要求:子查询的结果为单行单列(标量子查询)
    2、from后面
    要求:子查询的结果可以为多行多列
    3、where或having后面 ★
    要求:子查询的结果必须为单列
    单行子查询
    多行子查询
    4、exists后面
    要求:子查询结果必须为单列(相关子查询)

     


    特点:
    1、子查询放在条件中,要求必须放在条件的右侧
    2、子查询一般放在小括号中
    3、子查询的执行优先于主查询
    4、单行子查询对应了 单行操作符:> < >= <= = <>
    多行子查询对应了 多行操作符:any/some all in

    */
    #一、放在where或having后面
    #一)单行子查询

    #案例1:谁的工资比 Abel 高?


    #①查询Abel的工资
    SELECT salary
    FROM employees
    WHERE last_name = 'Abel'
    #②查询salary>①的员工信息
    SELECT last_name,salary
    FROM employees
    WHERE salary>(
    SELECT salary
    FROM employees
    WHERE last_name <> 'Abel'

    );

    #案例2:返回job_id与141号员工相同,salary比143号员工多的员工姓名,job_id 和工资
    #①查询141号员工的job_id
    SELECT job_id
    FROM employees
    WHERE employee_id = 141

    #②查询143号员工的salary

    SELECT salary
    FROM employees
    WHERE employee_id = 143

    #③查询job_id=① and salary>②的信息
    SELECT last_name,job_id,salary
    FROM employees
    WHERE job_id = (
    SELECT job_id
    FROM employees
    WHERE employee_id = 141
    ) AND salary>(

    SELECT salary
    FROM employees
    WHERE employee_id = 143

    );

    #案例3:返回公司工资最少的员工的last_name,job_id和salary

    #①查询最低工资
    SELECT MIN(salary)
    FROM employees

    #②查询salary=①的员工的last_name,job_id和salary
    SELECT last_name,job_id,salary
    FROM employees
    WHERE salary=(
    SELECT MIN(salary)
    FROM employees

    );

    #案例4:查询最低工资大于50号部门最低工资的部门id和其最低工资

    #①查询50号部门的最低工资
    SELECT MIN(salary)
    FROM employees
    WHERE department_id = 50


    #②查询各部门的最低工资,筛选看哪个部门的最低工资>①

    SELECT MIN(salary),department_id
    FROM employees
    GROUP BY department_id
    HAVING MIN(salary)>(

    SELECT MIN(salary)
    FROM employees
    WHERE department_id = 50
    );


    #二)多行子查询
    /*

    in:判断某字段是否在指定列表内
    x in(10,30,50)


    any/some:判断某字段的值是否满足其中任意一个

    x>any(10,30,50)
    x>min()

    x=any(10,30,50)
    x in(10,30,50)


    all:判断某字段的值是否满足里面所有的

    x >all(10,30,50)
    x >max()

    */


    #案例1:返回location_id是1400或1700的部门中的所有员工姓名

    #①查询location_id是1400或1700的部门
    SELECT department_id
    FROM departments
    WHERE location_id IN(1400,1700)


    #②查询department_id = ①的姓名
    SELECT last_name
    FROM employees
    WHERE department_id IN(
    SELECT DISTINCT department_id
    FROM departments
    WHERE location_id IN(1400,1700)

    );

    #题目:返回其它部门中比job_id为‘IT_PROG’部门任一工资低的员工的员工号、姓名、job_id 以及salary

    #①查询job_id为‘IT_PROG’部门的工资
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'


    #②查询其他部门的工资<任意一个①的结果

    SELECT employee_id,last_name,job_id,salary
    FROM employees
    WHERE salary<ANY(

    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'


    );

    等价于

    SELECT employee_id,last_name,job_id,salary
    FROM employees
    WHERE salary<(

    SELECT MAX(salary)
    FROM employees
    WHERE job_id = 'IT_PROG'


    );


    #案例3:返回其它部门中比job_id为‘IT_PROG’部门所有工资都低的员工 的员工号、姓名、job_id 以及salary

    #①查询job_id为‘IT_PROG’部门的工资
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'


    #②查询其他部门的工资<所有①的结果

    SELECT employee_id,last_name,job_id,salary
    FROM employees
    WHERE salary<ALL(

    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'


    );

    等价于

    SELECT employee_id,last_name,job_id,salary
    FROM employees
    WHERE salary<(

    SELECT MIN(salary)
    FROM employees
    WHERE job_id = 'IT_PROG'


    );


    #二、放在select后面

    #案例;查询部门编号是50的员工个数

    SELECT
    (
    SELECT COUNT(*)
    FROM employees
    WHERE department_id = 50
    ) 个数;


    #三、放在from后面

    #案例:查询每个部门的平均工资的工资级别
    #①查询每个部门的平均工资

    SELECT AVG(salary),department_id
    FROM employees
    GROUP BY department_id

    #②将①和sal_grade两表连接查询

    SELECT dep_ag.department_id,dep_ag.ag,g.grade
    FROM sal_grade g
    JOIN (

    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id

    ) dep_ag ON dep_ag.ag BETWEEN g.min_salary AND g.max_salary;


    #四、放在exists后面

    #案例1 :查询有无名字叫“张三丰”的员工信息
    SELECT EXISTS(
    SELECT *
    FROM employees
    WHERE last_name = 'Abel'

    ) 有无Abel;


    #案例2:查询没有女朋友的男神信息

    USE girls;

    SELECT bo.*
    FROM boys bo
    WHERE bo.`id` NOT IN(
    SELECT boyfriend_id
    FROM beauty b
    )

    SELECT bo.*
    FROM boys bo
    WHERE NOT EXISTS(
    SELECT boyfriend_id
    FROM beauty b
    WHERE bo.id = b.boyfriend_id
    );

     

     

     

     

     

     

     

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  • 原文地址:https://www.cnblogs.com/lcy1995/p/14716846.html
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