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  • SQL查询及删除重复记录的方法

    1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

    1. select * from people  
    2. where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)  
    select * from people
    where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)


    2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

    1. delete from people   
    2. where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)  
    3. and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)  
    delete from people 
    where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
    and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)


    3、查找表中多余的重复记录(多个字段)

    1. select * from vitae a  
    2. where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)  
    select * from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)


    4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

    1. delete from vitae a  
    2. where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)  
    3. and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)  
    delete from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
    


    5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

    1. select * from vitae a  
    2. where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)  
    3. and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)  
    select * from vitae a
    where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
    



    (二)
    比方说
    在A表中存在一个字段“name”,
    而且不同记录之间的“name”值有可能会相同,
    现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

    1. Select Name,Count(*) From A Group By Name Having Count(*) > 1  
    Select Name,Count(*) From A Group By Name Having Count(*) > 1


    如果还查性别也相同大则如下:

    1. Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1  
    Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

    (三) 方法一

    1. declare @max integer,@id integer  
    2.   
    3. declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1  
    4.   
    5. open cur_rows  
    6.   
    7. fetch cur_rows into @id,@max  
    8.   
    9. while @@fetch_status=0  
    10.   
    11. begin  
    12.   
    13. select @max = @max -1  
    14.   
    15. set rowcount @max  
    16.   
    17. delete from 表名 where 主字段 = @id  
    18.   
    19. fetch cur_rows into @id,@max  
    20.   
    21. end  
    22.   
    23. close cur_rows  
    24.   
    25. set rowcount 0  
    declare @max integer,@id integer
    
    declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1
    
    open cur_rows
    
    fetch cur_rows into @id,@max
    
    while @@fetch_status=0
    
    begin
    
    select @max = @max -1
    
    set rowcount @max
    
    delete from 表名 where 主字段 = @id
    
    fetch cur_rows into @id,@max
    
    end
    
    close cur_rows
    
    set rowcount 0




    方法二

    "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

    1、对于第一种重复,比较容易解决,使用

    1. select distinct * from tableName  
    select distinct * from tableName

      就可以得到无重复记录的结果集。

      如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

    1. select distinct * into #Tmp from tableName  
    2.   
    3. drop table tableName  
    4.   
    5. select * into tableName from #Tmp  
    6.   
    7. drop table #Tmp  
    select distinct * into #Tmp from tableName
    
    drop table tableName
    
    select * into tableName from #Tmp
    
    drop table #Tmp


      发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

    2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下

      假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

    1. select identity(int,1,1) as autoID, * into #Tmp from tableName  
    2.   
    3. select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID  
    4.   
    5. select * from #Tmp where autoID in(select autoID from #tmp2)  
    select identity(int,1,1) as autoID, * into #Tmp from tableName
    
    select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
    
    select * from #Tmp where autoID in(select autoID from #tmp2)




      最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

    (四) 查询重复

      1. select * from tablename where id in (select id from tablename group by id having count(id) > 1)  
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  • 原文地址:https://www.cnblogs.com/ld1022/p/3581183.html
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