【剑指offer】Q16：翻转链表

def reverse(head):
	if head == None or head.next == None:
		return head
	psuhead = ListNode(-1)
	while head:
		nexthead = head.next
		head.next = psuhead.next
		psuhead.next = head
		head = nexthead
	head = psuhead.next
	del psuhead
	return head

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原文地址：https://www.cnblogs.com/ldxsuanfa/p/10931019.html