zoukankan      html  css  js  c++  java
  • 888. Fair Candy Swap

    Alice and Bob have candy bars of different sizes: A[i] is the size of the i-th bar of candy that Alice has, and B[j] is the size of the j-th bar of candy that Bob has.

    Since they are friends, they would like to exchange one candy bar each so that after the exchange, they both have the same total amount of candy.  (The total amount of candy a person has is the sum of the sizes of candy bars they have.)

    Return an integer array ans where ans[0] is the size of the candy bar that Alice must exchange, and ans[1] is the size of the candy bar that Bob must exchange.

    If there are multiple answers, you may return any one of them.  It is guaranteed an answer exists.

    Example 1:

    Input: A = [1,1], B = [2,2]
    Output: [1,2]
    

    Example 2:

    Input: A = [1,2], B = [2,3]
    Output: [1,2]
    

    Example 3:

    Input: A = [2], B = [1,3]
    Output: [2,3]
    

    Example 4:

    Input: A = [1,2,5], B = [2,4]
    Output: [5,4]
    

    Note:

    • 1 <= A.length <= 10000
    • 1 <= B.length <= 10000
    • 1 <= A[i] <= 100000
    • 1 <= B[i] <= 100000
    • It is guaranteed that Alice and Bob have different total amounts of candy.
    • It is guaranteed there exists an answer.
    约束条件:只能交换一个糖 
    #include<iostream>
    #include<vector>
    #include<set>
    #include<unordered_set>
    using namespace std;
    class Solution {
    public:
        vector<int> fairCandySwap(vector<int>& A, vector<int>& B) {
            int sum_a=0;
            for (auto a: A) sum_a+=a;
            int sum_b=0;
            for (auto b: B) sum_b+=b;
            int diff=(sum_a-sum_b)/2;
            unordered_set<int> set_a(A.begin(),A.end());
            for(auto b: B){
                if(set_a.find(b+diff)!=set_a.end())
                    return {b+diff,b};
            }
        }
    };
    int main(){
        Solution solution;
        vector<int> A{1,2,5};
        vector<int> B{2,4};
        vector<int> res=solution.fairCandySwap(A, B);
        for(auto a: res)
            cout<<a<<" ";
        return 0;
    }
  • 相关阅读:
    工作中的体悟和经验
    java中List的toArray方法
    Arthas干货总结
    内部类访问外部类的方法
    PriorityBlockingQueue 源码分析
    ArrayBlockingQueue 源码解析
    Kafka 读书笔记--日志索引
    Mybatis源码解析之--谈谈${}
    Mybatis源码分析之--浅析ResultSetHandler
    linux命令--ll
  • 原文地址:https://www.cnblogs.com/learning-c/p/9847644.html
Copyright © 2011-2022 走看看