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  • 【LeetCode】House Robber III(337)

    1. Description

      The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all houses in this place forms a binary tree". It will automatically contact the police if two directly-linked houses were broken into on the same night.

      Determine the maximum amount of money the thief can rob tonight without alerting the police.  

      Example 1:

         3
        / 
       2   3
            
         3   1
    

      Maximum amount of money the thief can rob = 3 + 3 + 1 = 7.

      Example 2:

         3
        / 
       4   5
      /     
     1   3   1
    

      Maximum amount of money the thief can rob = 4 + 5 = 9.

    2. Answer

    /**
     * Definition for a binary tree node.
     * public class TreeNode {
     *     int val;
     *     TreeNode left;
     *     TreeNode right;
     *     TreeNode(int x) { val = x; }
     * }
     */
    public class Solution {
        public int rob(TreeNode root) {
            if (root == null)
                return 0;
            int first = root.val;
            int second = 0;
            if (root.left != null) {
                first += rob(root.left.left);
                first += rob(root.left.right);
                second += rob(root.left);
            }
            if (root.right != null) {
                first += rob(root.right.left);
                first += rob(root.right.right);
                second += rob(root.right);
            }
            
            return (first > second) ? first : second;    
        }
    }
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  • 原文地址:https://www.cnblogs.com/leesf456/p/5349176.html
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