LG P5043 树同构

( ext{problem})

无根树同构的判断

( ext{Analysis})

考虑树哈希，注意使用较正确的哈希方法
无根树同构有个性质
只要判断以这两棵树的重心为根是否同构即可

( ext{Code})

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;

const int N = 105, INF = 0x3f3f3f3f, P = 998244353;
int m, n, rt, siz[N], h[N], son[N], hash[N], tot;

struct edge{
	int to, nxt;
}e[N];
inline void add(int x, int y)
{
	e[++tot] = edge{y, h[x]}, h[x] = tot;
}

void getrt(int x, int fa)
{
	siz[x] = 1, son[x] = 0;
	for(int i = h[x]; i; i = e[i].nxt)
	{
		int v = e[i].to;
		if (v == fa) continue;
		getrt(v, x), siz[x] += siz[v];
		son[x] = max(son[x], siz[v]);
	}
	son[x] = max(son[x], n - siz[x]);
	rt = son[x] < son[rt] ? x : rt;
}

int hs[N][N], hv[N];
inline bool cmp(int x, int y){return hv[x] < hv[y];}
int dfs(int x, int fa)
{
	int res = 2021; hs[x][0] = 0, siz[x] = 1;
	for(int i = h[x]; i; i = e[i].nxt)
	{
		int v = e[i].to;
		if (v == fa) continue;
		dfs(v, x), siz[x] += siz[v], hs[x][++hs[x][0]] = v;
	}
	sort(hs[x] + 1, hs[x] + hs[x][0] + 1, cmp);
	for(int i = 1; i <= hs[x][0]; i++) res = ((long long)hv[hs[x][i]] * siz[hs[x][i]] + res) % P;
	return hv[x] = res;
}

int main()
{
	scanf("%d", &m), son[0] = INF;
	for(int j = 1; j <= m; j++)
	{
		scanf("%d", &n);
		tot = 0, memset(h, 0, sizeof h);
		for(int i = 1, x; i <= n; i++) 
		{
			scanf("%d", &x);
			if (x) add(x, i), add(i, x);
		}
		rt = 0, getrt(1, 0), hash[j] = dfs(rt, 0);
		for(int i = 1; i <= n; i++)
		if (i ^ rt && siz[i] == son[rt]) hash[j] = min(hash[j], dfs(i, 0));
		for(int i = 1; i <= j; i++)
		if (hash[i] == hash[j]){printf("%d
", i); break;}
	}
}