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  • LG P4148 简单题

    ( ext{Code})

    #include <cstdio>
    #include <iostream>
    #include <algorithm>
    #define re register
    using namespace std;
    
    const int N = 2e5 + 5;
    const double alpha = 0.725;
    int n, cur, x0, y0, x1, y1, rt;
    int L1[N], L2[N], R1[N], R2[N], siz[N], sum[N], ls[N], rs[N], ds[N], gs[N];
    struct node{int x, y, v;}s[N];
    inline bool cmpx(int a, int b){return s[a].x < s[b].x;}
    inline bool cmpy(int a, int b){return s[a].y < s[b].y;}
    
    inline void read(int &x)
    {
    	x = 0; char ch = getchar();
    	while (!isdigit(ch)) ch = getchar();
    	while (isdigit(ch)) x = (x << 3) + (x << 1) + (ch ^ 48), ch = getchar();
    }
    
    inline void update(int p, int o)
    {
    	L1[p] = min(L1[p], L1[o]), R1[p] = max(R1[p], R1[o]);
    	L2[p] = min(L2[p], L2[o]), R2[p] = max(R2[p], R2[o]);
    }
    inline void maintain(int p)
    {
    	siz[p] = siz[ls[p]] + siz[rs[p]] + 1, sum[p] = sum[ls[p]] + sum[rs[p]] + s[p].v;
    	L1[p] = R1[p] = s[p].x, L2[p] = R2[p] = s[p].y;
    	if (ls[p]) update(p, ls[p]); if (rs[p]) update(p, rs[p]);
    }
    
    int build(int l, int r)
    {
    	if (l > r) return 0;
    	int mid = (l + r) >> 1;
    	double av1 = 0, av2 = 0, s1 = 0, s2 = 0;
    	for(re int i = l; i <= r; i++) av1 += s[gs[i]].x, av2 += s[gs[i]].y;
    	av1 /= (r - l + 1), av2 /= (r - l + 1);
    	for(re int i = l; i <= r; i++)
    		s1 += (av1 - s[gs[i]].x) * (av1 - s[gs[i]].x), s2 += (av2 - s[gs[i]].y) * (av2 - s[gs[i]].y);
    	if (s1 > s2) nth_element(gs + l, gs + mid, gs + r + 1, cmpx), ds[gs[mid]] = 1;
    	else nth_element(gs + l, gs + mid, gs + r + 1, cmpy), ds[gs[mid]] = 2;
    	ls[gs[mid]] = build(l, mid - 1), rs[gs[mid]] = build(mid + 1, r), maintain(gs[mid]);
    	return gs[mid];
    }
    
    void getseq(int p){if (!p) return; getseq(ls[p]), gs[++gs[0]] = p, getseq(rs[p]);}
    inline void rebuild(int &p){gs[0] = 0, getseq(p), p = build(1, gs[0]);}
    inline int bad(int p){return max(siz[ls[p]], siz[rs[p]]) >= siz[p] * alpha;}
    
    void insert(int &p)
    {
    	if (!p) return void(maintain(p = cur));
    	if (ds[p] == 1)
    	{
    		if (s[cur].x <= s[p].x) insert(ls[p]);
    		else insert(rs[p]);
    	}
    	else{
    		if (s[cur].y <= s[p].y) insert(ls[p]);
    		else insert(rs[p]);
    	}
    	maintain(p);
    	if (bad(p)) rebuild(p);
    }
    
    int query(int p)
    {
    	if (!p || L1[p] > x1 || R1[p] < x0 || L2[p] > y1 || R2[p] < y0) return 0;
    	if (x0 <= L1[p] && R1[p] <= x1 && y0 <= L2[p] && R2[p] <= y1) return sum[p];
    	int res = 0;
    	if (s[p].x >= x0 && s[p].x <= x1 && s[p].y >= y0 && s[p].y <= y1) res = s[p].v;
    	return res + query(ls[p]) + query(rs[p]);
    }
    
    int main()
    {
    	read(n);
    	for(int opt = -1, last = 0; opt != 3; )
    	{
    		read(opt);
    		if (opt == 1)
    			++cur, read(s[cur].x), read(s[cur].y), read(s[cur].v),
    			s[cur].x ^= last, s[cur].y ^= last, s[cur].v ^= last, insert(rt);
    		else if (opt == 2) read(x0), read(y0), read(x1), read(y1),
    			x0 ^= last, y0 ^= last, x1 ^= last, y1 ^= last, printf("%d
    ", last = query(rt));
    	}
    }
    
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  • 原文地址:https://www.cnblogs.com/leiyuanze/p/15168211.html
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