JZOJ 3736. 【NOI2014模拟7.11】数学题

\(\text{Problem}\)

给出向量 \(\boldsymbol a = (x1,y1), \boldsymbol b = (x2,y2)\)
求 \(|\lambda_1\boldsymbol a + \lambda_2\boldsymbol b|\) 的最小值
其中 \(\lambda_1,\lambda_2\) 为整数

\(\text{Solution}\)

二维欧几里得算法的应用
然而并不懂是什么东西，我们只考虑这道题
做法见金斌的集训队论文《欧几里得算法的应用》

Here
注意共线的向量答案为 \(0\) 要特判

\(\text{Code}\)

#include <cstdio>
#include <cmath>
#include <iostream>
#define IN inline
using namespace std;

struct Vector{double x, y;}a, b;
IN double operator * (const Vector &a, const Vector &b){return a.x * b.x + a.y * b.y;}
IN Vector operator * (const Vector &a, double k){return Vector{a.x * k, a.y * k};}
IN Vector operator + (const Vector &a, const Vector &b){return Vector{a.x + b.x, a.y + b.y};}
IN Vector operator - (const Vector &a, const Vector &b){return Vector{a.x - b.x, a.y - b.y};}
IN double cos(Vector a, Vector b){return a * b / (sqrt(a * a) * sqrt(b * b));}

int main()
{
	freopen("math.in", "r", stdin), freopen("math.out", "w", stdout);
	while (~scanf("%lf%lf%lf%lf", &a.x, &a.y, &b.x, &b.y))
	{
		if (a * a > b * b) swap(a, b);
		if (a * b < 0) b = b * -1;
		double cos_alpha = cos(a, b);
		if (cos_alpha >= 1){printf("0\n"); continue;}
		while (cos_alpha > 0.5)
		{
			Vector c = b * cos_alpha;
			if (c * c < a * a) b = b - a;
			else b = b - a * (int)(sqrt(c * c) / sqrt(a * a));
			if (a * a > b * b) swap(a, b);
			if (a * b < 0) b = b * -1;
			cos_alpha = cos(a, b);
		}
		printf("%.0lf\n", min(a * a, b * b));
	}
}