sed指令进阶操作

删除

删除不匹配的第一行

sed -e '1!b' -e '/GH/!d' file

Linux SED script find the 1st line that match pattern and delete it

删除第一次匹配的行

echo -e "AB
MN2
MN3" | sed "0,/N/{//d;}"

How to conditionally remove first line only with sed when it matches?

参考资料

sed命令